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2 years ago

Which is larger 0.849 or 1.08

Mathematics

1 answer:

Anit [1.1K]2 years ago

5 0

Answer:

the answer to this question is 1.08

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Identify the geometric mean of 8 and 20 in simplest radical form.

Temka [501]

Answer:

8/x = x/20

x^2=160

x=sqrt(160)

x=sqrt(16*10)

x=sqrt(16)*sqrt(10)

x=4*sqrt(10)

Step-by-step explanation:

4 0

2 years ago

Steven is cutting an 11 ft piece of lumber into three pieces to build a triangular garden. Which diagram shows a way in which he

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D, can form a trangle

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4 years ago

Read 2 more answers

The four angles of a quadrilateral are in the ratio 2:3:5:8. Find the angles

sp2606 [1]

Answer:

Step-by-step explanation: let 2:3:5:8 be 2x,3x,5x,8x respectively .

*angles in a quadrilateral is 360 degree

*2x+3x+5x+8x=360

*18x=360

*x=360/18

*x=20

now substitute x in these:

2x=2x20=40

3x=3x20=60

5x=5x20=100

8x=8x20= 160

so these are the following angles: 40,60,100 and 160

8 0

4 years ago

40,000 is 10 times as much as

Dimas [21]

40,000 is 10 times as much as 4,000

3 0

3 years ago

An electronic product contains 48 integrated circuits. The probability that any integrated circuit is defective is 0.01, and the

BigorU [14]

Answer:

0.6173 = 61.73% probability that the product operates.

Step-by-step explanation:

For each integrated circuit, there are only two possible outcomes. Either they are defective, or they are not. The integrated circuits are independent. This means that we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

An electronic product contains 48 integrated circuits.

This means that $n = 48$

The probability that any integrated circuit is defective is 0.01.

This means that $p = 0.01$

The product operates only if there are no defective integrated circuits. What is the probability that the product operates?

This is P(X = 0). So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{48,0}.(0.01)^{0}.(0.99)^{48} = 0.6173$

0.6173 = 61.73% probability that the product operates.

5 0

3 years ago