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2 years ago

Can someone explain what to do like im a 5 year old please? (pre algebra)

Mathematics

1 answer:

QveST [7]2 years ago

3 0

Answer:

angle 3 = 61

angle 4 = 119

angle 6 = 61

angle 7 = 119

Step-by-step explanation:

there are a few ways you could look at this

first, each angle that is diagonal from eachother is going to be equal so 1 is the same as 3, 2 is the same as 4 etc

also each line going across has to be 180° so if angel 1 was 175 then angle 2 has to be 5 so when you combine them it becomes 180

if you look at the sizes some are bigger than the others, because you're given angle 1 = 61 then all the other small angles would be 61 too, and 180 - 61 = 119 so the all the big ones have to be 119

if this confused u more I'm sorry lol let me know if this helped

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Please help! i have no clue if it's equivalent :(

tensa zangetsu [6.8K]

Answer:

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

y+2=y+2

Step 2: Subtract y from both sides.

y+2−y=y+2−y

2=2

Step 3: Subtract 2 from both sides.

2−2=2−2

0=0

Answer:

All real numbers are solutions.

4 0

3 years ago

Read 2 more answers

if A(-2,1), B(1,5), C(4,4), D(1,0) are the vertices of a quadrilateral, do the points form a parallelogram? Justify your answer.

4vir4ik [10]

We have that

<span>A(-2,1), B(1,5), C(4,4), D(1,0)
</span>using a graph tool
see the attached figure

we know that
A parallelogram is a simple quadrilateral with opposite sides parallel and equal in length
therefore
<span>let's calculate the slope and distance of each side and compare them
</span>
side AB
slope m=(y2-y1)/(x2-x1)------> m=(5-1)/(1+2)----> m=4/3
distance AB=√4²+3³-------> dAB=5 units

side CD
slope m=(y2-y1)/(x2-x1)------> m=(0-4)/(1-4)----> m=4/3
distance CD=√4²+3³-------> dCD=5 units

side BC
slope m=(y2-y1)/(x2-x1)------> m=(4-5)/(4-1)----> m=-1/3
distance BC=√1²+3³-------> dBC=√10 units

side AD
slope m=(y2-y1)/(x2-x1)------> m=(0-1)/(1+2)----> m=-1/3
distance AD=√1²+3³-------> dAD=√10 units

(side BC and side AD are parallel) and (side BC=side AD)
and
(side AB and side CD are parallel) and (side AB=side CD)

therefore

the answer is
Yes, it is a parallelogram

5 0

4 years ago

The measure of b is ____.

Vedmedyk [2.9K]

Answer:

$\Huge\boxed{b=21}$

Step-by-step explanation:

Pythagorean Theorem:

$a^2+b^2=c^2$

where a and b = legs and c = hypotenuse

we are given a leg and the hypotenuse so we plug in what we have into the formula

$20^2+b^2=29^2$

now we solve for b

step 1 subtract 20^2 from each side

$b^2=29^2-20^2\\29^2=841\\2-^2=400\\841-400=441\\441=b^2$

finally we want to get rid of the exponent on the b

to do so we take the square root of each side

$\sqrt{441} =\sqrt{b^2} \\\sqrt{441} =21\\\sqrt{b^2} =b$

we're left with b = 21

Note: They Pythagorean theorem only works with right triangles

6 0

3 years ago

Use the addition-subtraction method to solve each of the following systems of equations.

inessss [21]

Answer:

1. x=2, y=3

2. n=7, m=-6.8

3. x=6, y=3

4. q=-2, p=-1

5. c=2, d=0

Step-by-step explanation:

4x + 3y = 17

5x – 3y = 1

first make it so either x or y can cancel out in both equations, then combine the equations, giving you 9x=18. solve for x, x=2. substitute 2 for x in either equation, 4(2) + 3y = 17. solve for y, 8+3y=17, 3y=9, y=3

–5m + 6n = –8

–5m + 8n = 6

first make it so either m or n can cancel out in both equations, multiply –5m + 6n = –8 by -1, 5m - 6n = 8, then combine the equations, giving you 2n=14. solve for n, n=7. substitute 7 for n in either equation, 5m - 6(7) = 8. solve for m, 5m - 42 = 8, 5m = -34, m = -6.8

2x – 7y = –9

6x + 7y = 57

first make it so either x or y can cancel out in both equations, then combine the equations, giving you 8x=48. solve for x, x=6. substitute 6 for x in either equation, 2(6) – 7y = –9. solve for y, 12 – 7y = –9, –7y = –21, y = 3

5p – 4q = 3

–5p – 4q = 13

first make it so either p or q can cancel out in both equations, then combine the equations, giving you -8q=16. solve for q, q=-2. substitute -2 for q in either equation, 5p – 4(-2) = 3. solve for p, 5p + 8 = 3, 5p = -5, p = -1

6c + d = 12

c – d = 2

first make it so either c or d can cancel out in both equations, then combine the equations, giving you 7c=14. solve for c, c=2. substitute 2 for c in either equation, 6(2) + d = 12. solve for d, 12 + d = 12, d = 0

[EDIT] question 2 is impossible.

5 0

4 years ago

How to put 8x - 7y = 23 into slope intercept form

viva [34]

Y = mx + b is the slope intersect form.

so 8x - 7y = 23
-7y = -8x + 23
y = -8x/-7 + 23/-7
y = 8/7x - 23/7 Ans

5 0

4 years ago