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3 years ago

I don’t understand this question

Mathematics

1 answer:

olchik [2.2K]3 years ago

3 0

Answer:

First pair: -4 and 8

Second pair: -2 and 6

Third pair: -1 and 5

Step-by-step explanation:

-4 + 8 = 4

-2 + 6 = 4

-1 + 5 = 4

Hope this helps

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Lisa is sitting on the dock beside the lake she drops a rock from her hand into the lake after the rock hits the surface of the

soldi70 [24.7K]

Answer: 4.2495 feets

Step-by-step explanation:

Given the following :

Rate of change (speed) when rock hits the lake surface = - 3in/s

Distance or depth after 5 seconds :

Distance = rate of change * time

Distance = (- 3 in/s × 5) = - 15 inches

1 inch = 0.0833 feet

15 inches = (-15 * 0.0833) = - 1.2495 feets

Distance between Lisa's hand and lake surface = 3 feets :

Distance between Lisa's hand and rock after 5 seconds :

(3 feets + 1.2495 feets) = 4.2495 feets

5 0

3 years ago

Does the set {t, t Int} form a fundamental set of solutions for t^2y" -- ty' +y = 0?

Ivanshal [37]

Answer:

yes

Step-by-step explanation:

We are given that a Cauchy Euler's equation

$t^2y''-ty'+y=0$ where t is not equal to zero

We are given that two solutions of given Cauchy Euler's equation are t,t ln t

We have to find the solutions are independent or dependent.

To find the solutions are independent or dependent we use wronskain

$w(x)=\begin{vmatrix}y_1&y_2\\y'_1&y'_2\end{vmatrix}$

If wrosnkian is not equal to zero then solutions are dependent and if wronskian is zero then the set of solution is independent.

Let $y_1=t,y_2=t ln t$

$y'_1=1,y'_2=lnt+1$

$w(x)=\begin{vmatrix}t&t lnt\\1&lnt+1\end{vmatrix}$

$w(x)=t(lnt+1)-tlnt=tlnt+t-tlnt=t$ where t is not equal to zero.

Hence,the wronskian is not equal to zero .Therefore, the set of solutions is independent.

Hence, the set {t , tln t} form a fundamental set of solutions for given equation.

6 0

3 years ago

Solve the system using the elimination method.

spayn [35]

Answer:

(x, y, z) = (-22/13, 29/13, 6/13)

Step-by-step explanation:

Adding the first and second equations, we get ...

(3x +2y -3z) +(7x -2y +5z) = (-2) +(-14)

10x +2z = -16 . . . . collect terms

5x + z = -8 . . . . . . divide by 2 . . . [eq4]

Adding twice the second equation to the third, we get ...

2(7x -2y +5z) +(2x +4y +z) = 2(-14) +(6)

16x +11z = -22 . . . . . . [eq5]

Now, we have two equations with the variable y eliminated. We can subtract [eq5] from 11 times [eq4] to eliminate z:

11(5x +z) -(16x +11z) = 11(-8) -(-22)

39x = -66

x = -66/39 = -22/13

From [eq4], we can find z as ...

z = -8 -5x = -8 -5(-22/13) = 6/13

And from the second equation, we get ...

y = (1/2)(7x +5z +14) = (1/2)(7(-22/13) +5(6/13) +14) = 29/13

The solution is (x, y, z) = (-22/13, 29/13, 6/13).

6 0

3 years ago

In a relay race, Nancy ran her part in 15.25 seconds, John ran his part in 13.8 seconds, Sylas ran his part in 16.4 seconds. Wha

sp2606 [1]

Answer:

45.45

Step-by-step explanation:

7 0

3 years ago

How to solve 6×+8 = 12x-4

Tatiana [17]

Answer:

x=2

Hope this helps!

8 0

3 years ago