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pashok25 [27]
2 years ago
6

There are 3 times as many males as females on the maths course at university. What fraction of the course are male?

Mathematics
1 answer:
exis [7]2 years ago
5 0

(1)

If there are three times as many males as females, the ratio of males to females would be 3:1.

To make this more clearer. Suppose you have 100 students. for each 4 students, 3 of them are male and 1 is a female.

We can then say there are 75 males and 25 females.

Expressing this as a ratio(fraction) is easy 3 out of 4 are males and 1 out of 4 are females. So the ratio of males would be;

r(m) =  \frac{3}{4}

(2)

Let x be the number of cola bottles

Let y be the number of smarties

Let z be the number of marshmallows

x=3y (since there are 3 times more x than y)

y=2z (since there are 2 times more y than z)

we know that marshmallows are twice as less as smarties. so for 1 marshmallow you'd have 2 smarties. But we also know that cola bottles should be 2×3=6 since we have 3 times more cola bottles than smarties.

Adding up our total sweets we get;

1+2+6=9

But how many of those are cola bottles? 6!

So the ratio of cola bottles can be expressed as,

r(c) =  \frac{6}{9}  =  \frac{2}{3}

You can simplify the numerator and denominator by 3 to get 2 over 3.

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-28/((-12+9)-(9+12/3)+1)
Mazyrski [523]
The answer is -1.86




3 0
3 years ago
Last year jo paid £245 for her car insurance. This year she paid£883 for her car insurance. What was the percentage increase
Kipish [7]

Answer:

72.2%

Step-by-step explanation:

Given data

Initial price=  £245

Final price= £883

% increase= Final - Initial / final  *100

% increase=883 - 245 / 245 *100

% increase= 638 / 883 *100

% increase=0.722*100

% increase=72.2%

Hence the increase is 72.2%

4 0
3 years ago
2. Starting at a fixed time, each car entering an intersection is observed to see whether it turns left (L), right (R), or goes
jasenka [17]

Answer:

Natural numbers (integers greater than zero)

X = 3,  5,  4,  4,  3

Step-by-step explanation:

The least number of cars that can be observed in this experiment is 1, if the first car turns left. On the other hand, the experiment could go on forever if no car ever turns left, thus the highest number of cars approaches infinite.

The possible values of X are integers greater than zero, which are known as the Natural numbers.

If X = number of cars observed, simply count the number of letters in each outcome for the value of X:

Outcome = RRL, AARRL, AARL, RRAL, ARL

            X = 3,  5,  4,  4,  3

7 0
3 years ago
Write an algebraic expression for the phrase. The quotient of 5 and the sum of 12 and a number x
anzhelika [568]

Answer:

the answer is (12 +x)/5 please mark brainliest

3 0
3 years ago
Solve for b 15=3b<br> Please I need help
IgorLugansk [536]
15=3b
15/3 = 3b/b
5= b

Isolate the variable by diving 3 on both sides
6 0
3 years ago
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