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2 years ago

Evaluate the expression when x = 3. x² + 6x - 3

Mathematics

1 answer:

Black_prince [1.1K]2 years ago

3 0

Answer:

X=3

${3}^{2} + 6(3) - 3 \\ 9 + 18 - 3 \\ 27 - 3 \\ = 24$

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3 years ago

One container is filled with mixture that is 25% acid. A second container is filled with a mixture that is 55% acid. The second

algol13

Answer:

Therefore the third container contains $\frac{735}{17}\%$ = 43.23 % acid.

Step-by-step explanation:

Given that, One container is filled with the mixture that 25% acid. 55% acid is contain by second container.

Let the volume of first container be x cubic unit.

Since the volume of second container is 55% larger than the first.

Then the volume of the second container is

$= (V\times \frac{100+55}{100})$ cubic unit.

$=\frac{155}{100}V$ cubic unit.

The amount of acid in first container is

$=V\times \frac{25}{100}$ cubic unit.

$=\frac{25}{100}V$ cubic unit.

The amount of acid in second container is

$=(\frac{155}{100}V \times \frac{55}{100})$ cubic unit.

$=\frac{8525}{10000}V$ cubic unit.

Total amount of acid $=(\frac{25}{100}V+\frac{8525}{10000}V)$ cubic unit.

$=(\frac{2500+8525}{10000}V)$ cubic unit.

$=(\frac{11025}{10000}V)$ cubic unit.

Total volume of mixture $=(V+\frac{155}{100}V)$ cubic unit.

$=\frac{100+155}{100}V$ cubic unit.

$=\frac{255}{100}V$ cubic unit.

The amount of acid in the mixture is

$=\frac{\textrm{The volume of acid}}{\textrm{The amount of mixture}}\times 100 \%$

$=\frac {\frac{11025}{10000}V}{\frac{255}{100}V}\times 100\%$

$=\frac{735}{17}\%$

Therefore the third container contains $\frac{735}{17}\%$ acid.

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3 years ago

What is 3x²+5x+25 when x equals 3

Ksivusya [100]

Answer: 67

Step-by-step explanation:

3x^2 + 5x + 25

x = 3

3(3)^2 + 5(3) + 25

3^2 = 9

3(9) + 5(3) + 25

3 * 9 = 27

27 + 5(3) + 25

5 * 3 = 15

27 + 15 + 25

27 + 15 = 42

42 + 25 = 67

8 0

3 years ago

Read 2 more answers