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2 years ago

Someone help me please

Mathematics

2 answers:

GenaCL600 [577]2 years ago

4 0

Answer:

3x + 5y = 15

Find gradient:

coordinates taken: (5, 0), (0, 3)

$\rightarrow \sf \dfrac{y_2-y_1}{x_2-x_1}$

$\rightarrow \sf \dfrac{3-0}{0-5}$

$\rightarrow \sf -\dfrac{3}{5}$

Here the y-intercept: 3

gradient: -3/5

equation:

$\sf \bold{ y = m(x) + b}$

$\rightarrow \sf y = -\dfrac{3}{5} x + 3$

$\rightarrow \sf y = -\dfrac{3}{5} x + \dfrac{15}{5}$

$\rightarrow \sf 5y =-3x+15$

$\rightarrow \sf 3x+5y =15$

viva [34]2 years ago

3 0

Take two points

(0,3)
(5,0)
x intercept=a=5
y intercept=b=3

equation of line in intercept form

$\\ \rm\rightarrowtail \dfrac{x}{a}+\dfrac{y}{b}=1$

$\\ \rm\rightarrowtail \dfrac{x}{5}+\dfrac{y}{3}=1$

Multiply each by 15

$\\ \rm\rightarrowtail 3x+5y=15$

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Give four different set of measurements that could be the dimension of the box are:

(l, w, h) = (2 , 15 , 2) feet and (2, 6, 5) feet and (2, 10, 3) feet and (3, 5, 4) feet

Solution:

Given that,

A card board box has a volume of 60 cubic feet

Cardboard box is of shape rectangular prism

The volume of rectangular prism is given as:

$\text{Volume of rectangular prism } = l \times w \times h$

Where,

l is the length

w is the width

h is the height

From given,

v = 60 cubic feet

$60 = l \times w \times h$

Give four different set of measurements that could be the dimension of the box:

Put l = 2 ; w = 15 ; h = 2

Then,

60 = 2 x 15 x 2

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Put l = 2 ; w = 6 ; h = 5

60 = 2 x 6 x 5

60 = 60

Put l = 2 ; w = 10 ; h = 3

60 = 2 x 10 x 3

60 = 60

Put l = 3 ; w = 5 ; h = 4

60 = 3 x 5 x 4

60 = 60

Thus, give four different set of measurements that could be the dimension of the box are:

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