SU is a midsegment of AQRT.
1 answer:
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Answer:
answer is 175
Step-by-step explanation:
i solved it by similarity in triangle small triangle and big triangle are similar to each other.
Therefore,DE=4y-8=4*6-8=16
And ,BE=y+10=6+10=16
=>BD=DE+EB=16+16=32
Hope This helps u...!!
And ,BE=y+10=6+10=16
=>BD=DE+EB=16+16=32
Hope This helps u...!!