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Alja [10]
2 years ago
12

|. Identify the following Pōints of each values.Write your ans

Mathematics
1 answer:
Dmitry_Shevchenko [17]2 years ago
7 0
<h2>✒️VALUE</h2>

\\ \quad  \begin{array}{c} \qquad \bold{Distance \: \green{ Formula:}}\qquad\\ \\ \boldsymbol{ \tt d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}} \end{array}\\  \begin{array}{l} \\ 1.)\: \bold{Given:}\: \begin{cases}\tt D(- 5,6), E(2.-1),\textsf{ and }F(x,0) \\ \tt DF = EF \end{cases} \\ \\  \qquad\bold{Required:}\:\textsf{ value of }x \\ \\ \qquad \textsf{Solving for }x, \\ \\  \tt  \qquad DF = EF \\ \\  \implies\small \tt{\sqrt{(x -(- 5))^2 + (0 - 6)^2} = \sqrt{(x - 2)^2 + (0 - (-1))^2}} \\ \\   \implies\tt\sqrt{(x + 5)^2 + 36 } = \sqrt{(x - 2)^2 + 1 } \\ \\ \textsf{Squaring both sides yields} \\ \\  \implies\tt (x + 5)^2 + 36 = (x - 2)^2 + 1 \\ \\  \implies\tt x^2 + 10x + 25 + 36 = x^2 - 4x + 4 + 1 \\ \\ \implies \tt x^2 + 10x + 61 = x^2 - 4x + 5 \\ \\   \implies\tt10x + 4x = 5 - 61 \\ \\   \implies\tt14x = -56 \\ \\  \implies \red{\boxed{\tt x = -4}}\end{array}  \\  \\  \\  \\\begin{array}{l} \\ 2.)\: \bold{Given:}\: \begin{cases}\tt P(6,-1), Q(-4,-3),\textsf{ and }R(0,y) \\ \tt PR = QR \end{cases} \\ \\ \bold{Required:}\:\textsf{ value of }y \\ \\  \qquad\textsf{Solving for }y, \\ \\  \qquad\tt PR = QR \\ \\  \implies \tt\small{\sqrt{(0 - 6)^2 + (y - (-1))^2} = \sqrt{(0 - (-4))^2 + (y - (-3))^2}} \\ \\   \implies\tt\sqrt{36 + (y + 1)^2} = \sqrt{16 + (y + 3)^2 } \\ \\ \textsf{Squaring both sides yields} \\ \\  \implies \tt \: 36 + (y + 1)^2 = 16 + (y + 3)^2 \\ \\  \implies\tt 36 + y^2 + 2y + 1 = 16 + y^2 + 6y + 9 \\ \\  \implies \tt \: y^2 + 2y + 37 = y^2 + 6y + 25 \\ \\  \implies \tt \: 2y - 6y = 25 - 37 \\ \\ \implies \tt -4y = -12 \\ \\   \implies\red{\boxed{ \tt y = 3}} \end{array}  \\  \\  \\ \begin{array}{l} \\ 3.)\: \bold{Given:}\: \begin{cases}\: A(4,5), B(-3,2),\textsf{ and }C(x,0) \\ \: AC = BC \end{cases} \\ \\ \bold{Required:}\:\textsf{ value of }x \\ \\  \qquad\textsf{Solving for }x, \\ \\   \qquad\tt AC = BC \\ \\ \implies\tt\small{\sqrt{(x - 4)^2 + (0 - 5)^2} = \sqrt{(x - (-3))^2 + (0 - 2)^2}} \\ \\ \implies\tt\sqrt{(x - 4)^2 + 25} = \sqrt{(x + 3)^2 + 4} \\ \\ \textsf{Squaring both sides yields} \\ \\ \implies\tt\:(x - 4)^2 + 25 = (x + 3)^2 + 4 \\ \\ \implies\tt\:x^2 - 8x + 16 + 25 = x^2 + 6x + 9 + 4 \\ \\ \implies\tt\:x^2 - 8x + 41 = x^2 + 6x + 13 \\ \\ \implies\tt-8x - 6x = 13 - 41 \\ \\\implies\tt -14x = -28 \\ \\ \implies\red{\boxed{\tt\:x = 2}} \end{array}

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100 POINTS PLEASE HURRY
Harlamova29_29 [7]

Answer:

5.80 to the power of 3. I would say this is the answer if you just look closely at the number line and you will see the answer

6 0
2 years ago
Read 2 more answers
11. Write the equation of a line in point-slope form
Vika [28.1K]

Answer:

Excuse me, wrong answer did not mean to type that. It would be C.

Step-by-step explanation:

This is because C. y - 5 = -2 (x+9) is an inequality. But, because of the slope of -2 passing through the point (-5, 9), it would be x - 9. So, C.

5 0
3 years ago
PLEASE HELP ME THANK YOU IF U DO
Andrews [41]

Answer:

B (r= 1/6s)

Step-by-step explanation:

If you just work out each option, you'll see that "s" multiplied by 1/6 gets r.

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2 years ago
Cameron is trying to find the equation of a line that
Alchen [17]
Yes it does I went on Desmos graphing Calculator and put in the equation and got those answers
5 0
3 years ago
A ball thrown straight up in the air travels 90 inches in the first tenth of a second. In the next tenth of a second the ball tr
Tcecarenko [31]

Answer:

855

Step-by-step explanation:

1.9 seconds is 19 tenths, so that means we add using the information given, which is that the ball travels 5 fewer inches every tenth of a second:

Time | Inches traveled

0.1     | 90

0.2    | 85

0.3    | 80

0.4    | 75

0.5    | 70

0.6    | 65

0.7    | 60

0.8    | 55

0.9    | 50

1.0     | 45

1.1      | 40

1.2     | 35

1.3     | 30

1.4     | 25

1.5     | 20

1.6     | 15

1.7     | 10

1.8     | 5

1.9     | 0

90+85+80+75+70+65+60+55+50+45+40+35+30+25+20+15+10+5+0=855

6 0
3 years ago
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