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CaHeK987 [17]
3 years ago
7

If tanθ= 2/5 find cosθ using identities. This is in quad. 1.

Mathematics
1 answer:
iren2701 [21]3 years ago
5 0

Answer: 5/2

Step-by-step explanation:

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Please find the square roots of the following complex number.
Nana76 [90]

Hey there,

First, find the square root of the given equation.

\sqrt{z}=\sqrt{81(\text{cos}(\frac{4\pi}{9})+i\text{sin}(\frac{4\pi}{9})}\\=9\text{cos}\frac{1}{2}(2k\pi+(\frac{4\pi}{9}))+i\text{sin}\frac{1}{2} (2k\pi+(\frac{4\pi}{9}))

Keep in mind that this is solved for k = 0 and 1.

Second, simplify.

=9\text{cos}(\frac{2\pi}{9})+i\text{sin}(\frac{2\pi}{9})~\text{or}~9\text{cos}(\frac{11\pi}{9})+i\text{sin}(\frac{11\pi}{9})

Best of Luck!

6 0
3 years ago
Classify the polynomial 4x^3-3x according to its degree and number of terms.
Ghella [55]
Degree is 3 and total of two terms.
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4 years ago
I'm having trouble with algebraic fractions . 3/2n-8/3=-29/12
nadezda [96]

what we can do is hmmmm get the LCD of all fractions, and multiply both sides by that LCD, let's see, we have denominators of 2, 3 and 12, so we can use the LCD of 12, and multiply both sides by 12 to do away with the denominators.

\bf \cfrac{3}{2}n-\cfrac{8}{3}=-\cfrac{29}{12}\implies \stackrel{\textit{multiplying both sides by }\stackrel{LCD}{12}}{12\left( \cfrac{3}{2}n-\cfrac{8}{3} \right)=12\left( -\cfrac{29}{12} \right)}\implies (6)3n-(4)8=(1)-29 \\\\\\ 18n-32=-29\implies 18n=3\implies n=\cfrac{3}{18}\implies n=\cfrac{1}{6}

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4 years ago
N + 4 > -9
Sav [38]

Answer:

n>-13

Step-by-step explanation:

so you subtract 4 from -9 then since your not multiplying or divinding by a negative you don't flip the sign

3 0
3 years ago
Read 2 more answers
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Nastasia [14]
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