Yes she would reach her goal
She skates 9/10 miles in the morning.
Then she skates 2/3 of 9/10 which is 3/5. You can find this out by multiplying the two fractions.
Once you got 3/5 you add 9/10 to it and you get 1 1/2
Hope this helps
Answer:
<h2>8</h2>
Step-by-step explanation:
![\text{The quadratic equation:}\ ax^2+bx+c=0.\\\\\text{We have}\ x^2-4x+2=0\\\\a=1,\ b=-4,\ c=2\\\\\text{Substitute to}\ b^2-4ac:\\\\b^2-4ac=(-4)^2-4(1)(2)=16-8=8](https://tex.z-dn.net/?f=%5Ctext%7BThe%20quadratic%20equation%3A%7D%5C%20ax%5E2%2Bbx%2Bc%3D0.%5C%5C%5C%5C%5Ctext%7BWe%20have%7D%5C%20x%5E2-4x%2B2%3D0%5C%5C%5C%5Ca%3D1%2C%5C%20b%3D-4%2C%5C%20c%3D2%5C%5C%5C%5C%5Ctext%7BSubstitute%20to%7D%5C%20b%5E2-4ac%3A%5C%5C%5C%5Cb%5E2-4ac%3D%28-4%29%5E2-4%281%29%282%29%3D16-8%3D8)
Answer:
BA = 25π,
LA = 25√2π,
TA = 25π + 25√2π,
V = 41 and 2 / 3π
Step-by-step explanation:
We need to determine the height here, as it is not given, and is quite important to us. The height is a perpendicular line segment to the radius, hence forming a 45 - 45 - 90 degree triangle as you can see. Therefore, by " Converse to Base Angles Theorem " the height should be equal in length to the radius,
( Height = 5 inches = Radius
______
Now knowing the height, let's begin by calculating the base area. By it's name, we have to find the area of the base. As it is a circle, let us apply the formula " πr^2 "
- Base Area = 25π
______
The lateral area is simply the surface area excluding the base area, the surface area having a formula of " πr^2 + πrl. " Thus, the lateral area can be calculated through the formula " πrl, " but as we are not given the slant height ( l ) we have to use another formula,
-
- Lateral Area = 25√2π
______
And the surface area is the base area + lateral area -
- Surface Area
______
The volume of a cone is 1 / 3rd that of a cylinder, with a simple formula of Base * height. Therefore, we can conclude the following -
- Volume = 41 and 2 / 3π
Answer:
25%
1/3
100%
5/4
2.5
Step-by-step explanation:
Convert all the values into decimals and order them from least to greatest.