Answer:
Step-by-step explanation:
f(x) = |2x−1|+3, reflected over the y-axis becomes
g(x) = |-2x−1|+3
We needed the point (0.5, 3) to go to the other side of the y-axis to get the point (-0.5, 3).
HELP ASAP
2 answers:
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X^a/b is ![\sqrt[b]{x^a}](https://tex.z-dn.net/?f=%20%5Csqrt%5Bb%5D%7Bx%5Ea%7D%20)
. The way I memorise that is x^1/3 is the cubic root of x. Do you get it? In that case, x is raised to a power of 1 and the cubic root is practically has a power of 3.
In your example,
![\sqrt[ \frac{3}{2} ]{16 x^4}](https://tex.z-dn.net/?f=%20%5Csqrt%5B%20%5Cfrac%7B3%7D%7B2%7D%20%5D%7B16%20x%5E4%7D)
is practically square rooting each term then cubing them individually. Remember when square-rooting any index you halve it. I'll elaborate:
= 
= 4
Then cube each,
= 64
and
= 
As for the 2nd part: you must use the rules of indices.
So breaking the question up:
3 * 3 = 9
stays as is since the 2nd term does not contain x
now:
This makes your final answer look like this:
I hope that helped and good luck in your test!
In your example,
Then cube each,
and
As for the 2nd part: you must use the rules of indices.
So breaking the question up:
3 * 3 = 9
now:
This makes your final answer look like this:
I hope that helped and good luck in your test!