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3 years ago

A pet store has m tanks of fish. Each tank has 35 fish. Using m, write an expression for the total number of fish in the store

Mathematics

1 answer:

11111nata11111 [884]3 years ago

7 0

Answer:

35m

Step-by-step explanation:

Each tank has 35 fish and the total fish tanks is m, so to find the total you will need to do 35*m.

This is an expression because it does not have anything it is equal to.

Expression: No equal sign

Equation:Equal Sign

Hope this helps!:)

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g100num [7]

Answer:

$-7 \frac{1}{2}$

Step-by-step explanation:

$\frac{6 {x}^{ - 1} {y}^{ \frac{7}{2} } }{ \sqrt{16 {x}^{2} } {y}^{2} } \\ \\ = \frac{6 {x}^{ - 1} {y}^{ \frac{7}{2} } }{ \sqrt{(4 {x} {y})^{2} }}\\ \\ = \frac{6 {x}^{ - 1} {y}^{ \frac{7}{2} } }{ {4 {x} {y}}}\\ \\ = \frac{6}{4} {x }^{ - 1 - 1} {y}^{ \frac{7}{2} - 1 } \\ \\ = \frac{3}{2} {x }^{ - 2} {y}^{ \frac{5}{2} } \\ \\ equating \: it \: with \: \\ a {x}^{b} {y}^{c} \\ \\ \implies \\ a = \frac{3}{2} \\ \\ b = - 2 \\ \\ c = \frac{5}{2} \\ \\ abc = \frac{3}{2} \times ( - 2) \times \frac{5}{2} \\ \\ = - \frac{15}{2} \\ \\ =- 7 \frac{1}{2} \\$

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4 years ago

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lesya [120]

Answer: the triangles are congruent

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3 years ago

She has 6 granola bars and 10 pieces of dried fruit. If each snack bag is identical without food left over what is the greatest

Rudik [331]

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Step-by-step explanation:

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3 years ago

A researcher wants to check the claim that convicted burglars spend less than 18.7 months in jail, on average. She takes a rando

vivado [14]

Answer:

a. No, there is not enough evidence to support the claim using a level of significance of 1%.

b. Null Hypothesis, $H_0$ : $\mu \geq$ 18.7 months

c. Alternate Hypothesis, $H_A$ : $\mu$ < 18.7 months

d. P-value of hypothesis test = 0.0199 or 1.99%

e. We conclude that the convicted burglars spend more than or equal to 18.7 months in jail, on average.

Step-by-step explanation:

We are given that a researcher wants to check the claim that convicted burglars spend less than 18.7 months in jail, on average.

She takes a random sample of 67 such cases from court files and finds that the mean is 16.8 months with a standard deviation of 7.3 months.

Let $\mu$ = true mean time convicted burglars spend in jail.

SO, Null Hypothesis, $H_0$ : $\mu \geq$ 18.7 months {means that the convicted burglars spend more than or equal to 18.7 months in jail, on average}

Alternate Hypothesis, $H_A$ : $\mu$ < 18.7 months {means that the convicted burglars spend less than 18.7 months in jail, on average}

The test statistics that will be used here is One-sample t test statistics as we don't know about the population standard deviation;

T.S. = $\frac{\bar X -\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean time spent in jail = 16.8 months

s = sample standard deviation = 7.3 months

n = sample of cases = 67

So, test statistics = $\frac{16.8-18.7}{\frac{7.3}{\sqrt{67} } }$ ~ $t_6_6$

= -2.13

Hence, the value of test statistics is -2.13.

Now, P-value of the test statistics is given by;

P-value = P( $t_6_6$ < -2.13) = 0.0199 or 1.99%

If the P-value of test statistics is more than the level of significance, then we will not reject our null hypothesis as it will not fall in the rejection region.

If the P-value of test statistics is less than the level of significance, then we will reject our null hypothesis as it will fall in the rejection region.

Now, here the P-value is 0.0199 or 1.99% which is clearly higher than the level of significance of 1%, so we will not reject our null hypothesis as it will not fall in the rejection region.

Therefore, we conclude that the convicted burglars spend more than or equal to 18.7 months in jail, on average.

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3 years ago

Brad sold candy bars and cookies for a fundraiser at school. Candy bars sold for $3, and cookies sold for $5. He sold a total of

kari74 [83]

Answer: First option

12 candy bars were sold

Step-by-step explanation:

Call x the amount of candy sold and call z the amount of cookies sold. Then we know that

$x + z = 20$