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4 years ago

15

Please help need help

1 answer:

Lemur [1.5K]4 years ago

5 0

The answer would be A,B,D

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Given the Arithmetic sequence A1,A2,A3,A4A1,A2,A3,A4

Bad White [126]

The given sequence is
a₁ = 29
a₂ = 39
a₃ = 49
a₄ = 59

This sequence is an arithmetic sequence. Th first term is a₁ = 29, and the common difference is d= 10.

The n-th term is
$a_{n}=a_{1}+(n-1)d$
The 33-rd termis
a₃₃ = 29 + (33 - 1)*10
= 29 + 320
= 349

Answer: a₃₃ = 349

7 0

3 years ago

Solve the system of equations Algebraically.

grandymaker [24]

Since y=x+3 (given)
Put value of y in equation x+y=(-3)
x+x+3=(-3)
2x=(-6)
x=(-3)
Put x=(-3) in x+y=(-3)
(-3)+y=(-3)
y=0
So, x=(-3)
y=0

4 0

3 years ago

2n +5)=2<br> Help me please

Kobotan [32]

Answer:

-1.5

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Two linear equations are shown. A coordinate grid with 2 lines. The first line is labeled y equals StartFraction one-third EndFr

Lorico [155]

Answer:

$(7,\frac{13}{3})$

Step-by-step explanation:

we have

<em>The equation of the first line</em>

$y=\frac{1}{3}x+2$ ------> equation A

<em>The equation of the second line</em>

$y=\frac{4}{3}x-5$ ------> equation B

Solve the system of equations by elimination

Multiply equation A by -4 both sides

$(-4)y=(-4)(\frac{1}{3}x+2)$

$-4y=-\frac{4}{3}x-8$ --------> equation C

Adds equation B and equation C

$y=\frac{4}{3}x-5\\-4y=-\frac{4}{3}x-8\\--------\\y-4y=-5-8\\-3y=-13\\y=\frac{13}{3}$

<em>Find the value of x</em>

substitute the value of y

$\frac{13}{3}=\frac{1}{3}x+2$

$\frac{1}{3}x=\frac{13}{3}-2$

Multiply by 3 both sides

$x=13-6$

$x=7$

therefore

The solution to the system of equations is the point $(7,\frac{13}{3})$

5 0

3 years ago

Read 2 more answers

Solve for y: 1.7-(3+2.4y) = 4(3y-2.91)

frez [133]

1.7-3-2.4y= 12y-11.64

-1.3-2.4y = 12y - 11.64

-2.4y = 12y - 11.64

-14.4y = -10.34

y= 10.34/14.4= 5.17/7.20 or 517/720

6 0

3 years ago