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2 years ago

Help help math math help

Mathematics

1 answer:

aliina [53]2 years ago

3 0

Answer:

The answer to this equation is 2

Step-by-step explanation:

x-2 = 3(2-x) \4

x-2= 6 -3x/4

cross multiply

4(x-2)= 6-3x

4x-8 = 6-3

collect like terms

4x+3x = 6+8

7x = 14

divide both sides by 7

7x/7= 14/7

x = 2

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F(x)=3x-6<br> how do I figure this out

vitfil [10]

F(x) = 3x-6
add 6 to each side
6=3x
dived each side by 3
2=x

3 0

4 years ago

Read 2 more answers

According to the Rational Root Theorem, the following are potential fox) 2x2 +2x 24.roots of -4, -3, 2, 3, 4Which are actual roo

aksik [14]

Correct Answer: First Option

Explanation:

There are two ways to find the actual roots:

a) Either solve the given quadratic equation to find the actual roots

b) Or substitute the value of Possible Rational Roots one by one to find out which satisfies the given equation.

Method a is more convenient and less time consuming, so I'll be solving the given equation by factorization to find its actual roots. To find the actual roots set the given equation equal to zero and solve for x as given below:

$2x^{2} +2x-24=0\\ \\ 2(x^{2} +x-12)=0\\ \\ x^{2} +x-12=0\\ \\ x^{2} +4x-3x-12=0\\ \\ x(x+4)-3(x+4)=0\\ \\ (x-3)(x+4)=0\\ \\ x-3=0, x=3\\ \\ or\\\\x+4=0, x=-4$

This means the actual roots of the given equation are 3 and -4. So first option gives the correct answer.

7 0

4 years ago

Read 2 more answers

in a 30-60-90 triangle, the hyptenuse has a length of 10. how long is the shorter leg (across from the 30 degree angle)?

larisa [96]

Answer:

5 units

Step-by-step explanation:

in a 30-60-90 triangle, the hypotenuse is 2 times the value of the shorter leg. So, if the hypotenuse is 10, then the shorter leg will be 5 units because 10 ÷ 2 is 5.

6 0

3 years ago

Solve this please!! I'm really stuck

lora16 [44]

Answer:

-74.

Step-by-step explanation:

First, notice that we can divide it into 2 equations (1 on each side of the equal symbol).

Replace where's x by -2 in the left equation:

$x+\:-4+\:-2(3x-5)=\square\mathrm{\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:replace\:x\:by\:-2}\\-2+\:-4+\:-2((3\cdot-2)-5)=\square\mathrm{\:\:\:\:solve\:the\:multiplication}\\-2-4-2(-6-5)=\square\mathrm{\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:remove\:excess\:symbols}\\-2-4-2(-11)=\square\mathrm{\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:solve\:multiplication}\\-2-4+22=\square\mathrm{\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:solve\:subtraction}\\16=\square$