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Anna71 [15]
3 years ago
10

How do you solve the system of equations for y=2x-4 y=4x-10

Mathematics
1 answer:
Ahat [919]3 years ago
6 0
\left\{\begin{array}{ccc}y=2x-4\\y=4x-10\end{array}\right\\\\subtitute:\\\\4x-10=2x-4\ \ \ \ \ |add\ 10\ to\ both\ sides\\4x=2x+6\ \ \ \ \ \ |subtract\ 2x\ from\ both\ sides\\2x=6\ \ \ \ \ \ |divide\ both\ sides\ by\ 2\\\boxed{x=3}\\\\y=2(3)-4\\y=6-4\\\boxed{y=2}
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Answer:

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Step-by-step explanation:

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Inga [223]

Answer:

A = 3

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Step-by-step explanation:

The way to format a quadratic equation is: ax^2 + bx + c, so the first step to solving this is to format it in the right way, where the x^2 comes first, the x second, and the number alone.

After formatting, your equation should look like this: 3x^2 - 5x + 2

From here, you can see the the <em>a </em> is 3, the <em>b</em> is -5, and the <em>c </em>is 2

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The answer is a 36
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