2 years ago

Find the critical value z alpha/2 that corresponds to the given confidence level 84%

SAT

1 answer:

ikadub [295]2 years ago

6 0

Answer:

c20

Explanation:

You might be interested in

A normal distribution of scores has a standard deviation of 10.

Lesechka [4]

5 is the answer to your question

6 0

2 years ago

What conclusion about gilgamesh can be drawn from this passage? what evidence best supports this conclusion?

pav-90 [236]

✔ He is a confident leader.

and

✔ He encourages Enkidu.

7 0

2 years ago

Alright guys this is the end thanks a lot I am trusting u guys that u get me a good grade please don't give me the wrong one

zepelin [54]

Answer:

1. b?

2. c

3. d

4. a

5. a

6. a

please don't trust my fully on this I'm dumb and those are just what i think are correct, sorry

Explanation:

8 0

3 years ago

Read 2 more answers

How many days do I have to wait to know my FSA score?

katovenus [111]

Answer:

Usually at the end of your school year or the beginning of your next school year

4 0

3 years ago

Read 2 more answers

B(n)=2^n A binary code word of length n is a string of 0's and 1's with n digits. For example, 1001 is a binary code word of len

Citrus2011 [14]

Answer:

The additional words is $2^n$

Explanation:

Given

$B(n) = 2^n$

Required

Determine the additional words; i.e. $B(n + 1) - B(n)$

From the given parameters, we have that;

B is a function of n

Such that;

$B(n) = 2^n$

To calculate $B(n+1)$ , we simply substitute n + 1 for n

$B(n) = 2^n$

$B(n + 1) = 2^{n + 1}$

Applying laws of indices

$B(n + 1) = 2^{n} * 2^1$

$B(n + 1) = 2^{n} * 2$

$B(n + 1) = 2(2^{n})$

Calculating Additional Binary Code;

$B(n + 1) - B(n)$

Substitute values for B(n + 1) and B(n)

$B(n + 1) - B(n) = 2(2^n) - 2^n$

Express $2^n$ as $2^ n * 1$

$B(n + 1) - B(n) = 2(2^n) - 2^n * 1$

Express 1 as $2^0$

$B(n + 1) - B(n) = 2(2^n) - 2^n * 2^0$

Factorize

$B(n + 1) - B(n) = 2^n(2 - 2^0)$

$B(n + 1) - B(n) = 2^n(2 - 1)$

$B(n + 1) - B(n) = 2^n(1)$

$B(n + 1) - B(n) = 2^n$

Hence, the additional words is $2^n$

8 0

3 years ago