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2 years ago

Solve for X and Y

Mathematics

1 answer:

Annette [7]2 years ago

3 0

Answer:

What do you mean?

Step-by-step explanation:

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4 years ago

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3 years ago

Put the equation in standard form with a positive x coefficient. 2y+5=-4(x+2)

umka21 [38]

The standard form of equation is: 4x+2y = -13

Step-by-step explanation:

the standard form of a linear equation in two variables is given by:

$ax+by = c$

Given equation is:

$2y+5=-4(x+2)$

Distributing -4 into the round bracket

$2y+5 = -4x-8$

Adding 4x on both sides

$4x+2y+5 = -4x-8+4x\\4x+2y+5 = -8$

subtracting 5 from both sides

$4x+2y+5-5 = -8-5\\4x+2y = -13$

The standard form of equation is: 4x+2y = -13

Keywords: Linear equation, variables

Learn more about linear equations at:

#LearnwithBrainly

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3 years ago

An investment is modeled by the function P = 2,500 (e) Superscript 0.025 t. What does 2,500 represent?

Setler [38]

Answer:

Step-by-step explanation:

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3 years ago

Read 2 more answers

Can someone help me in this plssss I really need it

kompoz [17]

Answer:

$\boxed{-3xy^{2}\sqrt [3] {2x^{2}}}$

Step-by-step explanation:

Your expression is

$\sqrt [3] {-54x^{5}y^{6}}$

Here's how I would simplify it.

$\begin{array}{rcll}\sqrt [3] {-54x^{5}y^{6}} & = & \sqrt [3] {(-1)^{3}\times 2 \times 27 \times x^{2} \times x^{3} \times y^{6}} & \text{Factored the cubes}\\& = & \sqrt [3] {(-1)^{3} \times 3^{3}\times x^{3} \times y^{6}\times 2 \times x^{2}} & \text{Grouped the cubes}\\\end{array}$

$\begin{array}{rcll}& = & \sqrt [3] {(-1)^{3} \times {3^{3}\times x^{3} \times y^{6}}} \times\sqrt [3] { 2 \times x^{2}} & \text{Separated the cubes}\\&=& \mathbf{-3xy^{2}\sqrt [3] {2x^{2}}} & \text{Took cube roots}\\\end{array}$

$\text{The simplified expression is $\boxed{\mathbf{-3xy^{2}\sqrt [3] {2x^{2}}}}$}$

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4 years ago