Answer:
C. -3
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtraction Property of Equality<u>
</u>
Step-by-step explanation:
<u>Step 1: Define</u>
-7x + 6 = 27
<u>Step 2: Solve for </u><em><u>x</u></em>
- [Subtraction Property of Equality] Subtract 6 on both sides: -7x = 21
- [Division Property of Equality] Divide -7 on both sides: x = -3
The annual rate of interest per year is 8%
<u>Solution:</u>
Given:- Principal (p) = 4600 rupees, Time –Period (t) = 5 years, Total amount(A) = 6440 rupees
First we will calculate the Interest and then using formula of simple interest we will calculate the rate of interest
Interest = Amount – Principal
Interest = 6440 – 4600 = 1840
Now using the formula of simple Interest and on putting values we get,

Where "P" is the principal and "R" is the rate of interest per annum and "T" is the time period


Hence, the required rate of interest per year is 8%
V(t) = 32t
when t = 3 seconds,
V = 32*3
V = 96
So velocity will be 96 units/s after 3 seconds.
Slope intercept form
y = mx + b:
10 = 7x + 3
y = 10
slope (m) = 7
b = 3
standard form:
Ax + By + C:
7x + 10y + 3
A = 7
B = 10
C = 3
hope this helps
<em>Answer,</em>
<em><u>S = -16</u></em>
<em>Explanation,</em>
<em><u>Step 1: Simplify both sides of the equation.</u></em>
<em>13 + 11s = − 15 + 8s − 20</em>
<em>13 + 11s = − 15 + 8s + − 20</em>
<em>11s + 13 = (8s) + (</em><em><u>− 15</u></em><em> + </em><em><u>− 20</u></em><em>) </em><em>(Combine Like Terms)</em>
<em>11s + 13 = 8s + − 35</em>
<em>11s + 13 = 8s − 35</em>
<em><u>Step 2: Subtract 8s from both sides.</u></em>
<em>11s + 13 − 8s = 8s − 35 − 8s</em>
<em>3s + 13 = − 35</em>
<em>Step 3: Subtract 13 from both sides.</em>
<em>3s + 13 − 13 = − 35 − 13</em>
<em>3s = − 48</em>
<em><u>Step 4: Divide both sides by 3.</u></em>
<em>3s/3 = −48/3</em>
<em>s = -16</em>
<u><em>Hope this helps :-)</em></u>