a and b are the two leg sides
c is the longest side.
a^2+b^2=c^2
a=x
b=9
c=11
a=c-b
11 squared is 121
9 squared is 81
121-81=40
The square root of 40, rounded to the nearest hundredth, is 6.32
Answer:
44u-36
Step-by-step explanation:
Apply the distributive property.
−6(−7u)−6⋅6+2u
Multiply −7 by −6.
42u−6⋅6+2u
Multiply −6 by 6.
42u−36+2u
Add 42u and 2u.
44u-36
Answer:
Area of the walkway border is 736 ft²
Step-by-step explanation:
A rectangle is a quadrilateral (has four sides and four angles) with two pairs of opposite and parallel sides. All angles in a rectangle are 90 degrees each. Also, opposite sides are equal.
The entire pool area has a length of 60 feet and width of 40 feet. The area of the entire pool area is:
Area of entire pool = length * width = 60 feet * 40 feet = 2400 ft²
The area of entire pool
A walkaway border of 4 ft is made around the pool area. There is a decrease of 4 ft round the sides of the pool area.
Therefore length of pool = length of entire pool area - 4 feet border at left - 4 feet border at right = 60 ft - 4 ft - 4 ft = 52 ft
width of pool = width of entire pool area - 4 feet border at top - 4 feet border at bottom = 40 ft - 4 ft - 4 ft = 32 ft
Therefore the pool is 52 ft × 32 ft
Area of pool = length * width = 52 ft * 32 ft = 1664 ft²
Area of the walkway border = Entire pool area - Area of pool = 2400 ft² - 1664 ft² = 736 ft²
I just graphed the table next to the graph of g and compared the two.
The y-intercept of f is (0,8) and the y-intercept of g is (0, -2). So f is GREATER THAN the y-intercept of g.
Now to do the average rate of change, I see from the interval [-6,-3] that f is decreasing and for g it is increasing. Thus f is LESS THAN the average rate of change of g.
Answer:
A = 99 cm²
Step-by-step explanation:
The area (A) of a triangle is calculated as
A =
bh ( b is the base and h the perpendicular height )
Here b = 18 and h = 11 , then
A =
× 18 × 11 = 9 × 11 = 99 cm²