2 years ago

Please help :) brainliest for helpful answers!

1 answer:

3 0

Using SohCahToa, you’ll find you have the opposite and adjacent, ao, so you’ll use tangent. Opp/adj is x/35 in this situation. You’ll take tan56 • 35 which is 51.9. That should be your answer.

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A line that includes the points (6,h) and (7,−10) has a slope of −7. What is the value of h ?

ozzi

Answer:

-3

Step-by-step explanation:

You can use $\frac{y_2-y_1}{x_2-x_1}$ to find the slope of a line going through $(x_1,y_1)$ and $(x_2,y_2)$ .

I like to line up the points and subtract vertically. Then put 2nd difference over 1st difference.

(6,h)

minus

(7,-10)

------------

-1 h-(-10)

$\frac{h-(-10)}{-1}$

This also said to be equal to -7:

$\frac{h+10}{-1}=-7$

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[texh=-3[/tex]

So if h=-3 then the slope of the line going through (6,h) and (7,-10) is -7.

Let's test it:

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The check is good.

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How do I simplify this? Include steps.<br> <img src="https://tex.z-dn.net/?f=%20%28%5Cfrac%7B5i%5E3t%5E4%7D%7B7%7D%29-2%20%20%20

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(5 (-i) t^4)/7 - 2 = (-5 i t^4)/7 - 14/7:
(-5 i t^4)/7 - 14/7
(-5 i t^4)/7 - 14/7 = (-5 i t^4 - 14)/7:
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