Answer:
As we look at the 2 numbers, we see a 2 and a 1 in the tenths places, 2 is greater than 1.
Therefore, 8.235 > 8.1
Best of Luck to you.
R= $42 rental cost per day
Mileage= $0.20 per mile
m= number of miles driven
Budget= $98 per day
EQUATION
$98> $0.20m + $42
SOLUTION
$98> $0.20m + $42
subtract 42 from both sides
$56> $0.20m
divide both sides by $0.20
280> m
They have to drive less than 280 miles per day to stay within their $98 budget.
SAME SOLUTION INEQUALITIES
Set up the equations with new numbers, substitute 280 for m and pick another variable to solve for. I chose to solve for total rental cost.
m= 280 miles per day
R= Rental cost per day
R> $0.10(280) + $50
R> $28 + $50
R> $78
Equation #1
$78> $0.10m + $50
----------
m= 280 miles per day
R= Rental cost per day
R> $0.18(280) + $44
R> $50.40 + $44
R> $94.40
Equation #2
$94.40> $0.18m + $44
ANSWER: 280> m; They have to drive less than 280 miles per day to stay within their $98 budget.
Equation #1: $78> $0.10m + $50
Equation #2: $94.40> $0.18m + $44
Hope this helps! :)
Well lets do the math
220 x 8 = 1760
1240 x 2 = 2480
2480 + 1760 = 4240
So we need 2 first class and 8 coach.
It becomes smallerr so its B
