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vladimir1956 [14]
3 years ago
14

This is part two of the questions

Mathematics
1 answer:
vodomira [7]3 years ago
5 0

Answer:

Step-by-step explanation:

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I am stuckk on this ​
shusha [124]

Answer:

192

try photo math

4 0
3 years ago
С<br> 5<br> ө<br> А:<br> 15<br> B<br> Nearest tenth
lubasha [3.4K]

Step-by-step explanation:

try 5 hope this helped you

5 0
3 years ago
The area of a square is 81square centimeters. First, find the length of a side. Then, find the length of the diagonal?
brilliants [131]
Part 1:

The length of a side is 9 cm.

The square root of 81 is 9. We have to find the square root bc we know it is a square.

Part 2:

The hypotenuse (or diagonal) is c.

Using the Pythagorean Theorem
a^{2}  +  {b}^{2}  =  {c}^{2}
you would know that 9 is a and b.

{9}^{2}   +  {9}^{2}  =  {c}^{2}
We know that
{9}^{2}  = 81
so you add 81 to 81.

81 + 81 = 162
81 and 81 make 162.

So you know ...

{c}^{2}  = 162
You take the square root of 162.

\sqrt{162}  = 12.73
well almost.

You can write your answer as

about \: 12.73 cm
or
\sqrt{162} cm

Hope I helped!
3 0
3 years ago
2. Evaluate f(3) for f(x) = 2x - 9
dedylja [7]

Answer:

-3

Step-by-step explanation:

f(x) = 2x - 9

f(3) = 2(3) - 9\\f(3) = 6 - 9\\f(3) = -3

4 0
3 years ago
Divide the following
vampirchik [111]
\frac{x^{2} - 4}{x - 8} \div \frac{x - 2}{1}
\frac{x^{2} + 2x - 2x - 4}{x - 8} \div \frac{x - 2}{1}
\frac{x(x) + x(2) - 2(x) - 2(2)}{x - 8} \div \frac{x - 2}{1}
\frac{x(x + 2) - 2(x + 2)}{x - 8} \div \frac{x - 2}{1}
\frac{(x - 2)(x + 2)}{x - 8} \div \frac{x - 2}{1}
\frac{x - 2}{x - 8}

The answer is C.
7 0
4 years ago
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