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Orlov [11]
2 years ago
11

Plss help asap!what fraction represents numbers between 21 - 27?

Mathematics
1 answer:
mel-nik [20]2 years ago
7 0

Answer:

0.7778

Step-by-step explanation:

step 1

Address the input parameters and observe what to be found:

Input values:

The fraction = 21/27

What to be found:

Find the decimal expansion of fraction 21/27.

step 2

The numerator is smaller than the denominator of the fraction 21/27, so find how many 10s should be multiplied with both numerator and denominator. Since the number of digits are equal in both numerator and denominator, multiply 10 with both numerator and denominator of 21/27.

=21

27

x10

10

step 3

Rearrange the fraction as like the below:

=10 x 21

27

x1

10

=210

27

x1

10

step 4

Simplify the above expression further:

=210

27

x1

10

=189 + 21

27

x1

10

= (189

27

+21

27

) x1

10

= (7 + 21

27

) x 1

10

step 5

Repeat the step 2 to find the decimal equivalent for the fraction 21/27 in the above expression:

= (7 + 21

27

) x 1

10

= (7 + 0.778) x1

10

step 6

Simplify the above expression further:

= (7 + 0.778) x1

10

= 7.778 x1

10

=7.778

10

21

27

= 0.7778

Hence,

21/27 as a decimal is 0.7778

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Step-by-step explanation:

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8 0
3 years ago
Read 2 more answers
B. Determine the values of a and b so that f is continuous.<br><br> Please help!
wlad13 [49]

Answer:

following are the solution to this question:

Step-by-step explanation:

Please find the complete question in the attached file.

\lim_{x\to 2}+f(x) = \lim_{x\to 2}+ (ax^2-bx+3) = 4a-2b+3\\\\ \to  4a-2b+3 = 4\\\\  \therefore \ \ 4a-2b = 1\\\\

The one-sided limits of F(x) at x = 3 must be equivalent for f(x) to be continuous at x = 3.

\to \lim_{x\to 3}- f(x) = \lim_{x\to 3}- (ax^2-bx+3) = 9a-3b+3\\\\ \to \lim_{x\to 3}+ f(x) = \lim_{x\to 3}+ (2x-a+b) = 6-a+b\\\\  

So,

\to 9a-3b+3 = 6-a+b\\\\\therefore\\ \to 10a -4b = 3

\to 4a - 2b = 1......(a)\\\to 10a - 4b = 3.......(b)\\

In equation a multiply the by -2 and then add in the equation b:

\to -8a + 4b = -2\\\to 10a - 4b = 3\\ \to 2a = 1\\\\ \to   a = \frac{1}{2}\\\\ \to \ 4(\frac{1}{2}) - 2b = 1\\\\ \to 2 - 2b = 1\\\\ \to   -2b = -1\\\\ \to b = \frac{1}{2}  

So, the value of a \ and \ b= \frac{1}{2}

4 0
2 years ago
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