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zhannawk [14.2K]
3 years ago
11

What are the solution(s) for the following quadratic equation?

Mathematics
1 answer:
ExtremeBDS [4]3 years ago
5 0

\\ \rm\rightarrowtail 5x^2-2x-7=0

\\ \rm\rightarrowtail 5x^2-7x+5x-7=0

\\ \rm\rightarrowtail x(5x-7)+1(5x-7)=0

\\ \rm\rightarrowtail (x-1)(5x-7)=0

\\ \rm\rightarrowtail x=1,7/5

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Answer:

1. 15 - 5n where n>=1

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Step-by-step explanation:

1. {10, 5, 0, -5, -10} is an Arithmetic Progression

nth term is a + (n - 1)d

where a = first term, n= nth term, d= common difference.

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Test:

if n = 1; 15 - 5(1) = 10

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2. {1, 4, 9, 16, 25}

The general term of the sequence is n²

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if n = 1; 1² = 1

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if n = 3; 3² = 9 and so on.

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