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zhannawk [14.2K]
3 years ago
11

What are the solution(s) for the following quadratic equation?

Mathematics
1 answer:
ExtremeBDS [4]3 years ago
5 0

\\ \rm\rightarrowtail 5x^2-2x-7=0

\\ \rm\rightarrowtail 5x^2-7x+5x-7=0

\\ \rm\rightarrowtail x(5x-7)+1(5x-7)=0

\\ \rm\rightarrowtail (x-1)(5x-7)=0

\\ \rm\rightarrowtail x=1,7/5

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What is (2.1 10^3) (4 10^ 7)?
brilliants [131]
8.4×10^10 or 84000000000
4 0
3 years ago
How many seconds will light leaving Los Angeles take to reach the following locations (a) San Francisco (about 500km), (b) Londo
kondor19780726 [428]

Answer:

a) It takes 0.0017s for the light to reach San Francisco.

b) It takes 0.033s for the light to reach London.

c) It takes 1.334s for the light to reach Mars.

d) It takes 149.7s for the light to reach Venus.

Step-by-step explanation:

Here we can solve this problem by using this following formula:

s = \frac{d}{t}

In which s is the speed(in km/s), d is the distance(in km) and t is the time(in s).

The light speed is 299 792 458 m / s = 299,792.458 km/s, so s = 299,792.458

(a) San Francisco (about 500km)

Find t when d = 500. So

s = \frac{d}{t}

299,792.458 = \frac{500}{t}

299,792.458t = 500

t = \frac{500}{299,792.458}

t = 0.0017s

It takes 0.0017s for the light to reach San Francisco.

b) London(about 10,000km)

Find t when d = 10,000. So

s = \frac{d}{t}

299,792.458 = \frac{10,000}{t}

299,792.458t = 10,000

t = \frac{10,000}{299,792.458}

t = 0.033s

It takes 0.033s for the light to reach London.

(c) the Moon (400,000km)

Find t when d = 400,000. So

s = \frac{d}{t}

299,792.458 = \frac{400,000}{t}

299,792.458t = 400,000

t = \frac{400,000}{299,792.458}

t = 1.334s

It takes 1.334s for the light to reach Mars.

(d) Venus (0.3 A.U. from Earth at its closest approach).

Each A.U. has 149,59,7871 km.

So 0.3 A.U. = 0.3*(149,597,871) = 44,879,361.3. This means that d = 44,879,361.3. So:

s = \frac{d}{t}

299,792.458 = \frac{44,879,361.3}{t}

299,792.458t = 44,879,361.3

t = \frac{44,879,361.3}{299,792.458}

t = 149.7s

It takes 149.7s for the light to reach Venus.

3 0
3 years ago
Enter a negative number that has an absolute value greater than 10
hammer [34]

Answer:

-11

Step-by-step explanation:

4 0
2 years ago
Which additional fact proves that ΔRST and ΔWXY are congruent if ∠T ≅ ∠Y and RT ≅ WY?
sergejj [24]

Answer:

Hence, option A is correct.

Step-by-step explanation:

We are asked to find the fact such that ΔRST and ΔWXY are congruent.

Since, we are given: ∠T ≅ ∠Y  and  RT ≅ WY.

we are given the following assumptions:

∠W = x + 5  

∠X = 3x - 9


∠Y = 2x + 4

as we are given one angle congruent and one side congruent so in order to prove two triangles are congruent we just need to show that one more pair of angles are congruent.

so from the two triangle we could have that ∠W≅∠R

and ∠X≅∠S

Now we will go by options:

A)

if ∠S=2x+20 then as ∠X≅∠S.

3x-9=2x+20

x=29

∠S=∠W=78°.

B)

if ∠R = 2x + 20 then as  ∠W≅∠R

⇒  x+5=2x+20

⇒ x= -15 which is not possible as it will make measure of angle W negative (x+5= -15+5= -10)

C)

if ∠S=2x^2+5 then as  ∠X≅∠S.

⇒ 3x-9=2x^2+5

⇒ 2x^2-3x+14=0

on solving this quadratic equation we will get complex zeros.

Hence, option (C) is not correct.

D)

if ∠R =  2x

^2

+ 5 then as ∠W≅∠R.

⇒ x+5=

2x

^2

+ 5

⇒ 2x^2-x=0

⇒ x(2x-1)=0

either x=0 or x=1/2 which is not  possible.

because by putting this x value in all the angles we see that sum of all the angles of a triangle is not equal  to 180°

Hence, option D is not possible.

Hence, option A is correct.



4 0
4 years ago
The sail on a boat is triangular and its area is 216 feet. If the length of the base of the sail is 18 feet, find its
finlep [7]

Answer:

24

Step-by-step explanation:

Use the triangle area formula: A=1/2 (base)(height)

Plug in what we know: 216=1/2(18)(h)

Solve for h: (1/2)(18)=9.

216/9=24.

So, h=24

To check, plug it into the formula: 1/2(18)(24)= 216

7 0
3 years ago
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