What are the solution(s) for the following quadratic equation?

1 answer:

5 0

$\\ \rm\rightarrowtail 5x^2-2x-7=0$

$\\ \rm\rightarrowtail 5x^2-7x+5x-7=0$

$\\ \rm\rightarrowtail x(5x-7)+1(5x-7)=0$

$\\ \rm\rightarrowtail (x-1)(5x-7)=0$

$\\ \rm\rightarrowtail x=1,7/5$

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