Recall that m(t) = m.(1/2)^t/h for radioactive decay, where h is the half-life. Suppose that a 500 g sample of phosphorus-32 decays to 356 g over 7 days. Calculate the half life of the sample.

Answer: The half life of the sample of phosphorus-32 is $14.28days^{-1}$

Step-by-step explanation:

The equation used to calculate the half life of the sample is given as:

$m(t)=m_o(1/2)^{t/h}$

where,

m(t) = amount of sample after time 't' = 356 g

$m_o$ = initial amount of the sample = 500 g

t = time period = 7 days

h = half life of the sample = ?

Putting values in above equation, we get:

$356=500\times (\frac{1}{2})^{7/h}\\\\h=14.28days^{-1}$

Hence, the half life of the sample of phosphorus-32 is $14.28days^{-1}$

7 0

3 years ago

Evaluate the expression for x=6 4×+6

alexira [117]

Answer:

Step-by-step explanation:

x=6

4 by 6 =24

24 + 6 =30

7 0

3 years ago

PLSSSSS HELPPPPPPPPP PLSSS

ra1l [238]

Answer:

Pretty sure it is A

Step-by-step explanation:

3 0

3 years ago

Brooks traded $5250 for Japanese yen, immediately changed his mind, and then promptly traded his Japanese yen back into dollars.

alukav5142 [94]

I Believe it would remain the same unless there is a fee for converting the dollar to yen in the first place.

8 0

3 years ago

Read 2 more answers