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ohaa [14]
2 years ago
12

In what areas is leslie's overspending

Mathematics
1 answer:
JulijaS [17]2 years ago
5 0

Answer:

is there a picture to answer?

Step-by-step explanation:

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Heather collects shells. The picture shows the 18 shells that she found on her family beach vacation. She wants to use all of
IRISSAK [1]
Answer:
D) 9 postcards with 2 shells each.

Explanation:
9 x 2 = 18
Therefore, 9 postcards with 2 shells each is the correct answer.

Please give brainliest.
6 0
2 years ago
A product is composed of four parts. In order for the product to function properly in a given situation, each of the parts must
nirvana33 [79]

Answer:

0.430

Step-by-step explanation:

Product has four parts :

For proper functioning, each part must function :

Let the 4 parts be:

A, B, C and D

Proper functioning probability :

A and B = 0.79

C and D = 0.83

For proper functioning :

P(A) * P(B) * P(C) * P(D)

0.79 * 0.79 * 0.83 * 0.83

= 0.42994249

= 0.430

3 0
3 years ago
A.<br> B.<br> C.<br> D.<br> Whats the answer
icang [17]
I think it’s c not so sure tho
3 0
3 years ago
Read 2 more answers
A sample of salary offers (in thousands of dollars) given to management majors is: 48, 51, 46, 52, 47, 48, 47, 50, 51, and 59. U
balu736 [363]

Answer:

Step-by-step explanation:

number of samples, n = 10

Mean = (48 + 51 + 46 + 52 + 47 + 48 + 47 + 50 + 51 + 59)/10 = 49.9

Standard deviation = √(summation(x - mean)/n

Summation(x - mean) = (48 - 49.9)^2 + (51 - 49.9)^2 + (46 - 49.9)^2+ (52 - 49.9)^2 + (47 - 49.9)^2 + (48 - 49.9)^2 + (47 - 49.9)^2 + (50 - 49.9)^2 + (51 - 49.9)^2 + (59- 49.9)^2 = 128.9

Standard deviation = √128.9/10 = 3.59

Confidence interval is written in the form,

(Sample mean - margin of error, sample mean + margin of error)

The sample mean, x is the point estimate for the population mean.

Margin of error = z × s/√n

Where

s = sample standard deviation

From the information given, the population standard deviation is unknown and the sample size is small, hence, we would use the t distribution to find the z score

In order to use the t distribution, we would determine the degree of freedom, df for the sample.

df = n - 1 = 10 - 1 = 9

Since confidence level = 95% = 0.95, α = 1 - CL = 1 – 0.95 = 0.05

α/2 = 0.05/2 = 0.025

the area to the right of z0.025 is 0.025 and the area to the left of z0.025 is 1 - 0.025 = 0.975

Looking at the t distribution table,

z = 2.262

Margin of error = 2.262 × 3.59/√10

= 2.57

the lower limit of this confidence interval is

49.9 - 2.57 = 47.33

the lower limit of this confidence interval is

49.9 + 2.57 = 52.47

So it is false

6 0
3 years ago
Whats 1/18 as a decimal can someone please help me
sergij07 [2.7K]

1/18 as a decimal is 0.055555555555556 because you divide one by eighteen and get that number.

Hope this helped!

6 0
2 years ago
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