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Illusion [34]
2 years ago
14

15.4 segment relationships in circles homework answers

SAT
1 answer:
MakcuM [25]2 years ago
7 0

The length of the segment is an illustration of intersecting chords

The value of x is x = 27/14

<h3>How to determine the length of the segment?</h3>

From the complete question (see attachment), we have:

AD = 12

AE = 3

BE = 14

EC = x

Start by calculating the length of ED

ED = AD - AE

This gives

ED =12 - 3

ED =9

The value of x is then calculated as:

x * BE = AE * ED

Substitute known values

x * 14 = 3 * 9

Evaluate the product

x * 14 = 27

Divide both sides by 14

x = 27/14

Hence, the value of x is x = 27/14

Read more about intersecting chords at:

brainly.com/question/13950364

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In portfolio margin, equity options and stocks are tested with /- 15% price changes.~If you buy $100,000 worth of ABCD stock, wh
zavuch27 [327]

The portfolio margin requirement is mathematically given as

M = 15,000

This is further explained below.

<h3> What is the portfolio margin requirement?</h3>

Generally, the equation for  Margin requirement is mathematically given as

M= 15% of 100,000

Therefore

M = 15,000

In conclusion,  The portfolio margin requirement is mathematically given as

M = 15,000

Read more about  portfolio margin

brainly.com/question/14308426

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6 0
2 years ago
What is one characteristic that indicates the first passage is fictional while the second is non-fictional?
netineya [11]

Answer:

D

Explanation:

Characters(Unless it says otherwise)  are all fictional, but the passage can present facts.

4 0
3 years ago
A chef fills 50ml container with 43.5 g of cooking oil. what is the density of the oil​
tino4ka555 [31]

Answer:

.87

Explanation:

(Density is mass divided by Volume)

D

=

M

V

D

=

43.5g

50ml

=

.87

5 0
3 years ago
A sample of a compound that contains only the elements c, h, and n is completely burned in o2 to produce 44. 0 g of co2, 45. 0 g
Elan Coil [88]

Answer:

B. CH₅N

Explanation:

The combustion reaction of a compound CₐHₓNₙ with O₂ is:

CₐHₓNₙ + O₂ → a CO₂ + X/2 H₂O + n NO₂

Where 1 mole of CₐHₓNₙ with an excess of O₂ produce a moles of CO₂, X/2 moles of H₂O and n moles of NO₂

Thus, you need to convert the mass of CO₂ and H₂O to moles to find the C:H ratio and determine a possible empirical formula thus:

Moles CO₂ (Molar mass 44g/mol):

44g ₓ (1mol / 44g) = 1 mole CO₂ = 1 mole C

Mole of H₂O (Molar mass 18g/mol):

45g ₓ (1 mol / 18g) = 2.5 moles H₂O = 5 moles H

Thus, in the compound you have 5 moles of H per mole of C, and a possible empirical formula is:

B. CH₅N

The only structure that meet this C:H ratio

8 0
3 years ago
H o w yo u guys b e e n :)))))))))))
Akimi4 [234]

Answer:

i've been better. how about you?

Explanation:

6 0
3 years ago
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