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1 year ago

5

Events that cannot happen at the same time are called?

1 answer:

AveGali [126]1 year ago

5 0

If you want to find out use the voice thing and figure it out for like example heads and tails on a coin you can clearly see them those things are almost alike now you can do this just believe in yourself

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A new app charges an annual fee plus an additional fee per new game downloaded. The table shows the linear relationship between

gogolik [260]

The correct answer is below:

6 0

2 years ago

The 5th term in a geometric sequence is 160. The 7th term is 40. What are possible values of the 6th term of the sequence?

omeli [17]

Answer:

C. The 6th term is positive/negative 80

Step-by-step explanation:

Given

Geometric Progression

$T_5 = 160$

$T_7 = 40$

Required

$T_6$

To get the 6th term of the progression, first we need to solve for the first term and the common ratio of the progression;

To solve the common ratio;

Divide the 7th term by the 5th term; This gives

$\frac{T_7}{T_5} = \frac{40}{160}$

Divide the numerator and the denominator of the fraction by 40

$\frac{T_7}{T_5} = \frac{1}{4}$ ----- equation 1

Recall that the formula of a GP is

$T_n = a r^{n-1}$

Where n is the nth term

So,

$T_7 = a r^{6}$

$T_5 = a r^{4}$

Substitute the above expression in equation 1

$\frac{T_7}{T_5} = \frac{1}{4}$ becomes

$\frac{ar^6}{ar^4} = \frac{1}{4}$

$r^2 = \frac{1}{4}$

Square root both sides

$r = \sqrt{\frac{1}{4}}$

r = ± $\frac{1}{2}$

Next, is to solve for the first term;

Using $T_5 = a r^{4}$

By substituting 160 for T5 and ± $\frac{1}{2}$ for r;

We get

$160 = a \frac{1}{2}^{4}$

$160 = a \frac{1}{16}$

Multiply through by 16

$16 * 160 = a \frac{1}{16} * 16$

$16 * 160 = a$

$2560 = a$

Now, we can easily solve for the 6th term

Recall that the formula of a GP is

$T_n = a r^{n-1}$

Here, n = 6;

$T_6 = a r^{6-1}$

$T_6 = a r^5$

$T_6 = 2560 r^5$

r = ± $\frac{1}{2}$

So,

$T_6 = 2560( \frac{1}{2}^5)$ or $T_6 = 2560( \frac{-1}{2}^5)$

$T_6 = 2560( \frac{1}{32})$ or $T_6 = 2560( \frac{-1}{32})$

$T_6 = 80$ or $T_6 = -80$

$T_6 =$ ±80

Hence, the 6th term is positive/negative 80

8 0

2 years ago

Solve the equation 3(x+2)=5(x-2)

Sladkaya [172]

Answer:

<em><u>3</u></em><em><u>(</u></em><em><u> </u></em><em><u>x </u></em><em><u>+</u></em><em><u> </u></em><em><u>2</u></em><em><u> </u></em><em><u>)</u></em><em><u>. </u></em><em><u>=</u></em><em><u> </u></em><em><u>5</u></em><em><u>(</u></em><em><u> </u></em><em><u>x </u></em><em><u>-</u></em><em><u> </u></em><em><u>2</u></em><em><u>)</u></em>

<em><u>3</u></em><em><u>x</u></em><em><u> </u></em><em><u>+</u></em><em><u> </u></em><em><u>6</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>5</u></em><em><u>x</u></em><em><u> </u></em><em><u>-</u></em><em><u> </u></em><em><u>1</u></em><em><u>0</u></em>

<em><u>-2x </u></em><em><u>=</u></em><em><u> </u></em><em><u>-</u></em><em><u> </u></em><em><u>1</u></em><em><u>6</u></em><em><u> </u></em>

<em><u>minus,</u></em><em><u>minus </u></em><em><u>cancel</u></em>

<em><u>x </u></em><em><u>=</u></em><em><u> </u></em><em><u>1</u></em><em><u>6</u></em><em><u>/</u></em><em><u>2</u></em><em><u> </u></em>

<em><u>x </u></em><em><u>=</u></em><em><u> </u></em><em><u>8</u></em><em><u> </u></em>

8 0

2 years ago

Read 2 more answers

Plz answer rn plzzzzzzzz

Leviafan [203]

Answer: correct

Step-by-step explanation: if you distribute the 9 to the 2+x you’d get two factors 18 and 9x

3 0

1 year ago

Please help. I will mark brainleist

Kitty [74]

Can I see the options?

7 0

3 years ago