Find the equation of the line that is perpendicular to Y=6x+3 and passes through the point (-24,5)
1 answer:
The slope of the given line is the coefficient of x, 6. The slope of the perpendicular line will be the negative reciprocal of that, -1/6. Then the point-slope form of the equation of the line is
y = m(x -h) +k . . . . . . line with slope m through point (h, k)
You want m=-1/6, (h, k) = (-24, 5), so your equation is
y = (-1/6)(x +24) +5
y = (-1/6)x +1
y = m(x -h) +k . . . . . . line with slope m through point (h, k)
You want m=-1/6, (h, k) = (-24, 5), so your equation is
y = (-1/6)(x +24) +5
y = (-1/6)x +1
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Answer:
B.)
Step-by-step explanation:
use the slope rule
Fill in values
Simplify
Simplify further
Done.
After you measured it you can check if the measurement is correct by knowing radius and arc length using formula,
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Hope this helps.