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patriot [66]
2 years ago
14

What is the value of sin-1(1)? negative startfraction pi over 2 endfraction 0 startfraction pi over 2 endfraction π

Mathematics
1 answer:
mariarad [96]2 years ago
3 0

The value of sin-1(1) is negative startfraction pi over 2 endfraction, startfraction -pi over 2 endfraction.

<h3>What is the value of sin (π/2)?</h3>

The value of sin (π/2) is equal to the number 1. The value of the sin-1(1) has to be find out.

Suppose the value of this function is <em>x</em>. Thus,

x=\sin^{-1}(1)

Solve it further,

\sin(x)=(1)              ......1

The value of sin (π/2) and -sin (-π/2) is equal to 1 such that,

\sin\dfrac{\pi}{2}=-\sin\left(-\dfrac{\pi}{2}\right)=1

Put this value in the equation 1,

\sin(x)=\sin\left(\dfrac{\pi}{2}\right)=-\sin\left(-\dfrac{\pi}{2}\right)

Thus, the range will be,

\left(\dfrac{\pi}{2},-\dfrac{\pi}{2}\right)

Thus, the value of sin-1(1) is negative startfraction pi over 2 endfraction, startfraction -pi over 2 endfraction.

Learn more about the sine values here;

brainly.com/question/10711389

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<h2><em><u>A</u></em><em><u>N</u></em><em><u>S</u></em><em><u>W</u></em><em><u>E</u></em><em><u>R</u></em></h2>

<em><u>H</u></em><em><u>e</u></em><em><u>r</u></em><em><u>e</u></em><em><u> </u></em><em><u>t</u></em><em><u>h</u></em><em><u>e</u></em><em><u> </u></em><em><u>t</u></em><em><u>w</u></em><em><u>o</u></em><em><u> </u></em><em><u>p</u></em><em><u>o</u></em><em><u>i</u></em><em><u>n</u></em><em><u>t</u></em><em><u>s</u></em><em><u> </u></em><em><u>g</u></em><em><u>i</u></em><em><u>v</u></em><em><u>e</u></em><em><u>n</u></em><em><u> </u></em><em><u>o</u></em><em><u>n</u></em><em><u> </u></em><em><u>t</u></em><em><u>h</u></em><em><u>e</u></em><em><u> </u></em><em><u>g</u></em><em><u>r</u></em><em><u>a</u></em><em><u>p</u></em><em><u>h</u></em><em><u> </u></em><em><u>A</u></em><em><u> </u></em><em><u>a</u></em><em><u>n</u></em><em><u>d</u></em><em><u> </u></em><em><u>B</u></em>

<em><u>T</u></em><em><u>o</u></em><em><u> </u></em><em><u>f</u></em><em><u>i</u></em><em><u>n</u></em><em><u>d</u></em><em><u> </u></em><em><u>:</u></em><em><u> </u></em><em><u> </u></em><em><u>T</u></em><em><u>h</u></em><em><u>e</u></em><em><u> </u></em><em><u>d</u></em><em><u>i</u></em><em><u>s</u></em><em><u>t</u></em><em><u>a</u></em><em><u>n</u></em><em><u>c</u></em><em><u>e</u></em><em><u> </u></em><em><u>i</u></em><em><u>n</u></em><em><u> </u></em><em><u>b</u></em><em><u>e</u></em><em><u>t</u></em><em><u>w</u></em><em><u>e</u></em><em><u>e</u></em><em><u>n</u></em><em><u> </u></em><em><u>t</u></em><em><u>h</u></em><em><u>e</u></em><em><u> </u></em><em><u>t</u></em><em><u>w</u></em><em><u>o</u></em><em><u> </u></em><em><u>p</u></em><em><u>o</u></em><em><u>i</u></em><em><u>n</u></em><em><u>t</u></em><em><u>s</u></em><em><u> </u></em><em><u>w</u></em><em><u>e</u></em><em><u> </u></em><em><u>k</u></em><em><u>n</u></em><em><u>o</u></em><em><u>w</u></em><em><u> </u></em><em><u>d</u></em><em><u>i</u></em><em><u>s</u></em><em><u>t</u></em><em><u>a</u></em><em><u>n</u></em><em><u>c</u></em><em><u>e</u></em><em><u> </u></em><em><u>i</u></em><em><u>n</u></em><em><u> </u></em><em><u>b</u></em><em><u>e</u></em><em><u>t</u></em><em><u>w</u></em><em><u>e</u></em><em><u>e</u></em><em><u>n</u></em><em><u> </u></em><em><u>t</u></em><em><u>w</u></em><em><u>o</u></em><em><u> </u></em><em><u>p</u></em><em><u>o</u></em><em><u>i</u></em><em><u>n</u></em><em><u>t</u></em><em><u> </u></em><em><u>o</u></em><em><u>n</u></em><em><u> </u></em><em><u>a</u></em><em><u> </u></em><em><u>g</u></em><em><u>r</u></em><em><u>a</u></em><em><u>p</u></em><em><u>h</u></em><em><u> </u></em>

<em><u>=</u></em><em><u> </u></em>

<em><u>\sqrt{ {(x2 - x1)}^{2} }  +  \sqrt{ {(y2 - y1)}^{2} }</u></em>

<em><u>T</u></em><em><u>h</u></em><em><u>e</u></em><em><u> </u></em><em><u>P</u></em><em><u>o</u></em><em><u>i</u></em><em><u>n</u></em><em><u>t</u></em><em><u> </u></em><em><u>A</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>(</u></em><em><u>0</u></em><em><u>,</u></em><em><u>0</u></em><em><u>)</u></em>

<em><u>T</u></em><em><u>h</u></em><em><u>e</u></em><em><u> </u></em><em><u>p</u></em><em><u>o</u></em><em><u>i</u></em><em><u>n</u></em><em><u>t</u></em><em><u> </u></em><em><u>B</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>(</u></em><em><u>3</u></em><em><u>,</u></em><em><u>6</u></em><em><u>)</u></em>

<em><u>s</u></em><em><u>o</u></em><em><u> </u></em><em><u>t</u></em><em><u>h</u></em><em><u>e</u></em><em><u> </u></em><em><u>d</u></em><em><u>i</u></em><em><u>s</u></em><em><u>t</u></em><em><u>a</u></em><em><u>n</u></em><em><u>c</u></em><em><u>e</u></em><em><u> </u></em><em><u>i</u></em><em><u>n</u></em><em><u> </u></em><em><u>b</u></em><em><u>e</u></em><em><u>t</u></em><em><u>w</u></em><em><u>e</u></em><em><u>e</u></em><em><u>n</u></em><em><u> </u></em><em><u>p</u></em><em><u>o</u></em><em><u>i</u></em><em><u>n</u></em><em><u>t</u></em><em><u>s</u></em><em><u> </u></em><em><u>A</u></em><em><u> </u></em><em><u>a</u></em><em><u>n</u></em><em><u>d</u></em><em><u> </u></em><em><u>B</u></em><em><u> </u></em>

<em><u>\sqrt{ {(0 - 0)}^{2} }  +  \sqrt{ {(6 - 3)}^{2} }</u></em>

<em><u>\sqrt{ {3}^{2} }</u></em>

<em><u>3</u></em>

So 3.0 is the distance

Hope it helps

7 0
2 years ago
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