The nth term of a sequence is n2 + 5 (a) (i) Find the first two terms of this sequence. (ii) Is 126 a term of this sequence? You
1 answer:
Answer:
126 is a term in the sequence. Please check my assumption on the correct formula.
Step-by-step explanation:
I will assume that n2 + 5 is actually n^2 + 5.
Starting with n=0, use the formula to calculate successive values of n. The attached table is the result of n from 0 to 22. At n=11, the result is 126, so 126 is a term in the sequence.
If the expression is actually n2 + 5, calculate the values for y = 2n + 5. 126 would not be a term in this sequence.
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Here is your answer:
In order to find your answer we will have to solve each option separately to see which one equals 6 × 5.
<---- Not the answer
<----- Not the answer
<---- Your answer
Therefore your answer is option C "6 + 6 + 6 + 6 + 6 ."
Hope this helps!