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barxatty [35]
2 years ago
9

What is the value of the y-intercept of the graph f(x)=138⋅1.9x?

Mathematics
1 answer:
REY [17]2 years ago
3 0

Answer:

Step-by-step explanation:

The y-intercept is the point where the graph cuts the y axis - that is when x = 0.

f(x)=138⋅1.9x

ehen x = 0 f(x) = 0 so the y-intercept is at (0, 0).

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T -1 4/9 +4 5/9 = 3 2/9<br><br><br> Solve for t plz!
g100num [7]

Answer: T= 1/9

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2 years ago
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Determine if x + 2 is a factor of p(x) = x ^4 + 3x^ 3 + 4x ^2 - 8 and explain why.
zlopas [31]
X^4+ 3x^3+4x^2-8 |   x+2   =  x^3+x^2+2x-4
 -x^4-2x^3
-----------------------     
         x^3+4x^2-8
         -x^3-2x^2
-------------------------
                 2x^2-8
                 -2x^2-4x
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                    4x+8
----------------------------
                      / /

is a factor because (x+2)(x^3+x^2+2x-4)=x^4+3x^3+4x^2-8
4 0
3 years ago
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3 years ago
(3x2 + 8x − 3) ÷ (x + 3)?
Fittoniya [83]

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6 0
3 years ago
A cooler contains fifteen bottles of sports drink: eight lemon-lime flavored and seven orange flavored
dem82 [27]

Answer:

Mutually exclusive,

P(\text{Lemon-lime or orange})=\frac{2}{3}

Step-by-step explanation:

Please consider the complete question:

Determine if the scenario involves mutually exclusive or overlapping events. Then find the  probability.

A cooler contains twelve bottles of sports  drink: four lemon-lime flavored, four  orange flavored, and four fruit-punch  flavored. You randomly grab a bottle. It  is a lemon-lime or an orange.

Let us find probability of finding one lemon lime drink.

P(\text{Lemon-lime})=\frac{\text{Number of lemon lime drinks}}{\text{Total drinks}}

P(\text{Lemon-lime})=\frac{4}{12}

P(\text{Lemon-lime})=\frac{1}{3}

Let us find probability of finding one orange drink.

P(\text{Orange})=\frac{\text{Number of orange drinks}}{\text{Total drinks}}

P(\text{Orange})=\frac{4}{12}

P(\text{Orange})=\frac{1}{3}

Since probability of choosing a lemon lime doesn't effect probability of choosing orange drink, therefore, both events are mutually exclusive.

We know that probability of two mutually exclusive events is equal to the sum of both probabilities.

P(\text{Lemon-lime or orange})=P(\text{Lemon-lime})+P(\text{Orange})

P(\text{Lemon-lime or orange})=\frac{1}{3}+\frac{1}{3}

P(\text{Lemon-lime or orange})=\frac{1+1}{3}

P(\text{Lemon-lime or orange})=\frac{2}{3}

Therefore, the probability of choosing a lemon lime or orange is \frac{2}{3}.

8 0
3 years ago
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