Question

How would I solve this problem?

Answer 1

Answer:

$2x^2$

Step by step explanation:

$y=\displaystyle \int_{0}^x 2t^2 dt=\dfrac 23\left[t^3\right]^{x}_0=\dfrac 23 x^3\\\\\ y'= \dfrac 23 \cdot 3x^2 = 2x^2$