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pshichka [43]
2 years ago
12

How do you determine the period and frequency based of these coordinate points?

Mathematics
1 answer:
alexgriva [62]2 years ago
3 0

Answer:

The formula for period is T = 1 / f , where "T" is period – the time it takes for one cycle to complete, and "f" is frequency.

To get period from frequency, first convert frequency from Hertz to 1/s.

Now divide 1 by the frequency. The result will be time (period) expressed in seconds.

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John took a 5 ½ mile walk to his friend’s house. He left at 11 a.m. and arrived at his friend’s house at 1 p.m. What was John’s
olganol [36]

Answer:

5.5 miles over 2 hours--> 5.5/2= 2.75 miles per hour was his average walking speed. 5.5 miles over 2.5 hours --> 5.5/2.5= 2.2 miles per hour on the return trip meaning that his average speed was (2.75-2.2= 0.55) 0.55 miles per hour lower on the return trip

Step-by-step explanation:

I hope this helps you :)

<em><u>-KeairaDickson</u></em>

7 0
3 years ago
Describe how to simplify the expression (3^-6)/(3^-4). Answers: Divide the bases and then add the exponents. Keep the base the s
Viktor [21]

Answer:

Last option: Keep the base the same and then subtract the exponents.

Step-by-step explanation:

There is a property called "Quotient of power property".

This property states that if you need to divide two powers with the same base, you must keep the same base and subtract the exponents:

\frac{a^m}{a^n}=a^{(m-n)}

Then, you need to apply this property to the expression \frac{(3^{-6})}{(3^{-4})} to simplify it.

Therefore, you get that the expression simplified is:

3^{(-6-(-4))}=3^{(-6+4)}=3^{-2}

8 0
3 years ago
Read 2 more answers
Evaluate f(x) = -x to the second power + 1 for x = -3
professor190 [17]
I think it's 4 Yeah 4 something like that
5 0
3 years ago
A spherical balloon is inflating with helium at a rate of 6464piπ StartFraction ft cubed Over min EndFraction ft3 min. How fast
Dmitrij [34]

Answer:

the surface area​ will increase 16  feet per minute

Step-by-step explanation:

Allow me to revise your question for a better understanding.

<em>A spherical balloon is inflating with helium at a rate of 64π Start Fraction ft cubed Over min End Fraction ft3 min. How fast is the​ balloon's radius increasing at the instant the radius is 2 ​ft? How fast is the surface area​ increasing? </em>

My answer:  

Given that:

\dfrac{dV}{dt} = 64\pi \dfrac{\text{ ft}^3}{\text{min}}  (1)

As we know that, the volume of a  spherical balloon can be calculated by using the following formula:

V = \dfrac{4}{3}\pi r^3 where r is the radius

Substitute V into (1), we have:

\dfrac{dV}{dt} = \dfrac{d}{dt}(\dfrac{4}{3}\pi r^3)\\\\\dfrac{dV}{dt} =4\pi r^2\dfrac{dr}{dt}

In this situation, the instant radius is: 2f

So we have:

64\pi = 4\pi (2)^2\dfrac{dr}{dt}\\\\\Rightarrow \dfrac{dr}{dt} = 4

The radius of the balloon is increasing at a rate of 4 feet per minute

The the surface area​ has the formula as:

SA1 = 4πr^{2}

If the radius of the balloon is increasing at a rate of 4 feet per minute, so the

the surface area​ will increase 16  feet per minute  because:

SA2 : 4π(4r)^{2}  = 16 (4πr^{2} ) = 16 SA1

Hope it will find you well.

8 0
4 years ago
Three jackets cost as much as five shirts. Each jacket costs $16 more
juin [17]

Answer:

$3.20

Step-by-step explanation:

Divide the number 16 (as in the cost per Jacket) by 5. (The amount of shirts you could buy with $16)

Then once you have divided 16 by 5, your answer should be 3.2, so the cost of one shirt is $3.20

6 0
3 years ago
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