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NARA [144]
3 years ago
10

FIRST TO ANSWRR GETS 30 POINTS!

Mathematics
1 answer:
Fantom [35]3 years ago
5 0

Answer:

a) £600

b) £1400

Step-by-step explanation:

a)  Set up a ratio of price to percentage of original price.

Let x = original price

⇒ £420 : 70 = £x : 100%

\sf \implies 420 : 70  = x : 100

\sf \implies \dfrac{420}{70}=\dfrac{x}{100}

\sf \implies x=100\cdot\dfrac{420}{70}

\sf \implies x=600

Therefore, the original price of the bracelet was £600

b) Set up a ratio of price to percentage of original price.

If the ring is reduced by 40% then it is now 60% of the original price, since 100% - 40% = 60%

Let x = original price

⇒ £840 : 60% = £x : 100%

\sf \implies 840 : 60  = x : 100

\sf \implies \dfrac{840}{60}=\dfrac{x}{100}

\sf \implies x=100\cdot\dfrac{840}{60}

\sf \implies x=1400

Therefore, the original price of the ring was £1400

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a volley ball player servers the ball. The ball follows a path given by the equation y=-0.01x^2+0.5x+3 where x and y are measure
dolphi86 [110]

Answer:

(a)

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(b)

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Step-by-step explanation:

we are given

The ball follows a path given by the equation

y=-0.01x^2+0.5x+3

where

x and y are measured in feet and the origin is on the court directly below where the player hits the ball

(a)

net height is 8 ft

so, we can set y=8

and then we can solve for x

8=-0.01x^2+0.5x+3

8\cdot \:100=-0.01x^2\cdot \:100+0.5x\cdot \:100+3\cdot \:100

800=-x^2+50x+300

-x^2+50x-500=0

x^2-50x+500=0

we can use quadratic formula

x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

x=\frac{-50\pm \sqrt{50^2-4\left(-1\right)\left(-500\right)}}{2\left(-1\right)}

x=5\left(5-\sqrt{5}\right),\:x=5\left(5+\sqrt{5}\right)

x=13.82,x=36.2

So, distance from player should be 13.82 feet or 36.2 feet

(b)

we can plug x=30 and check whether y=8 ft

y=-0.01(30)^2+0.5(30)+3

y=9ft

we know that

height of net is 8 ft

so, the ball will go over the net


5 0
4 years ago
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