By using trigonometric relations, we will see that x = 9.97°.
<h3>
How to find the missing angle?</h3>
First, we need to find the bottom cathetus of the smaller triangle, we will use the relation:
Tan(θ) = (opposite cathetus)/(adjacent cathetus).
Where:
- θ = 26°
- Adjacent cathetus = k
- Opposite cathetus = 55ft.
Replacing that we get:
Tan(26°) = 50ft/k
Solving this for k, we get:
k = 55ft/tan(26°) = 112.8 ft
Now, we can see that the longer triangle adds 200ft to this cathetus, so now we will have:
- angle = x
- opposite cathetus = 55ft
- adjacent cathetus = 112.8ft + 200ft = 312.8ft.
Then we have:
Tan(x) = (55ft/312.8ft)
Using the inverse tangent function in both sides, we get:
x = Atan(55ft/312.8ft) = 9.97°
If you want to learn more about right triangles, you can read:
brainly.com/question/2217700
Answer:
6s + 2s - 3s - 6:
5s-6
10t - 4t -6 + 5t:
11t-6
18r + 18r + 9r - 3r:
42r
20 - 4q + 40r - 16:
-4q+40r+4
17st - 16s + t:
17st-16s+t
. 101+101x - x:
101+100x
16a2 - 14a + a2 - 3a:
14 ato the power of 2- 17a
14t + 14t + t:
29t
r + s + rs + s + rs + s:
r+2rs+3s
54 pt - 3p + 4t - 3pt:
51pt-3p+4t
i dont know 11
101c - 5c +4c:
100c
12q - 4 + 10q - 4q +9:
18q+5
21k - 20k + 3k:
4k
181x + 91x - 23x:
249x
Step-by-step explanation:
120 degrees or 0.67 radians
Answer:
22.35 m/s
Step-by-step explanation:
The distance is always a positive unit, so distance traveled (d) = 15 miles
Time (t) = 0.3 hours
Time (t) = 0.3 * 60 = 18 minutes
(1 hour = 60 minutes)
Velocity (v) = ?
The formula of distance is: d = v*t
=> v = d/t = 15/18 = 0.83 miles/minute
we can also calculate velocity is meter/sec, for that
1 minute = 60 sec
=> 18 mins = 18*60 = 1080 sec
1 mile = 1609.34 meters
=> 15 miles = 15 * 1609.34 = 24,140 m
hence,
v = 24,140/1080 = 22.35 m/s
Which transformations can be used to map a triangle with vertices A(2, 2), B(4, 1), C(4, 5) to A’(–2, –2), B’(–1, –4), C’(–5, –4
jek_recluse [69]
Notice that every pair of point (x, y) in the original picture, has become (-y, -x) in the transformed figure.
Let ABC be first transformed onto A"B"C" by a 90° clockwise rotation.
Notice that B(4, 1) is mapped onto B''(1, -4). So the rule mapping ABC to A"B"C" is (x, y)→(y, -x)
so we are very close to (-y, -x).
The transformation that maps (y, -x) to (-y, -x) is a reflection with respect to the y-axis. Notice that the 2. coordinate is same, but the first coordinates are opposite.
ANSWER:
"<span>a 90 clockwise rotation about the origin and a reflection over the y-axis</span>"