Based on the calculations, the pressure inside this droplet is equal to 2,909.35 kPa.
<u>Given the following data:</u>
- Surface tension = 0.00518 lbf/ft to N/m = 0.00702 N/m.
- Atmospheric pressure = 14.7psia to kPa = 101.35 kPa.
- Diameter = 0.01 mm to m = 0.00001 m.
Radius, r =
= 0.000005 m.
<h3>How to determine the pressure inside a droplet.</h3>
For a droplet with only one surface, its pressure is given by this formula:
![P_1-P_2=\frac{2 \tau}{r} \\\\P_1=\frac{2 \tau}{r}+P_2](https://tex.z-dn.net/?f=P_1-P_2%3D%5Cfrac%7B2%20%5Ctau%7D%7Br%7D%20%5C%5C%5C%5CP_1%3D%5Cfrac%7B2%20%5Ctau%7D%7Br%7D%2BP_2)
Substituting the given parameters into the formula, we have;
![P_1=\frac{2 \times 0.00702}{0.000005} + 101.35\\\\P_1=2808+ 101.35](https://tex.z-dn.net/?f=P_1%3D%5Cfrac%7B2%20%5Ctimes%200.00702%7D%7B0.000005%7D%20%2B%20101.35%5C%5C%5C%5CP_1%3D2808%2B%20101.35)
Inside pressure = 2,909.35 kPa.
Read more on pressure here: brainly.com/question/24827501