Carlos purchased an antique chair for $15 he later so this year for $27 to an antique dealer what was the percent markup of the

Question

IRINA_888 [86]

4 years ago

15

Carlos purchased an antique chair for $15 he later so this year for $27 to an antique dealer what was the percent markup of the

chair

Mathematics

2 answers:

Rama09 [41] · Answer 1 · 2021-11-23T23:33:37+03:00

Rama09 [41]4 years ago

6 0

Okay. So, to find the percent change, we have to do change/original. In this case, it would be 12/15, because 15 and 27 are apart by 12. 12/15 is 0.8. Multiply that by 100 and you get 80. There was an 80% markup of the chair sold to the antique dealer.

jasenka [17] · Answer 2 · 2021-11-24T00:52:49+03:00

Answer: The required percent markup is 80%.

Step-by-step explanation: Given that Carlos purchased an antique chair for $15 and later he sold it this year for $27 to an antique dealer.

We are to find the percent markup of the chair.

The markup price of the chair is given by

$m_p=\$(27-15)=\$12.$

Since Carlos purchased the chair for $15, so the markup percent is given by

$\dfrac{m_p}{15}\times100\%\\\\\\=\dfrac{12}{15}\times100\%\\\\\\=\dfrac{4}{5}\times100\%\\\\=80\%.$

Thus, the required percent markup is 80%.