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ladessa [460]
2 years ago
6

Sketch a graph of − 3 x − y = − 4

Mathematics
1 answer:
kykrilka [37]2 years ago
7 0

Answer:

Step-by-step explanation:

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Simplify by using the distributive property 3-2(2x+2)-(4x+2)
OleMash [197]

3-2(2x+2)-(4x+2)

Pretend that there is a -1 in front of the second bracket

3-2(2x+2)-1(4x+2)

Multiply the first bracket by 2

Multiply the second bracket by -1

(-2)(2x)(-2)(2)=-4x-4

(-1)(4x)(-1)(2)= -4x-2

3-4x-4-4x-2

-4x-4x+3-4-2

Do 3-4-2 first

3-4-2

-1-2

=-3

-4x-4x-3

-8x-3

Answer: -8x-3

5 0
3 years ago
For what missing value is the equation an identity? <br> -2(2x-?)+1=17-4x
solong [7]
The missing value is 8
6 0
4 years ago
What is 2/9 + 4/9 in simplesst form
Viefleur [7K]

Answer:

2/3

Step-by-step explanation:

since the two fractions have the same denominator, you can add the numerators together to get the answer. 2/9+4/9=6/9. since 6 and 9 are both divisible by 3, you divide both numbers by 3, making the answer 2/3.

8 0
3 years ago
A cylindrical bale of hay has a diameter of 5 feet and a height of 6 feet. What volume of hay does the bale contain. Round to th
snow_lady [41]

Answer:471

Step-by-step explanation: 5 squared is 25 you multiply that by 3.14 then multiply that by 6

4 0
3 years ago
NO LINKS!! Please help me with this problem​
12345 [234]

Answer:

\frac{x^2}{784}+\frac{y^2}{400}=1

Step-by-step explanation:

<u><em>Horizontal Major Axis:</em></u>

   \frac{(x-h)^2}{a^2}+\frac{(y-k)^2}{b^2}

<u><em>Vertical Major Axis:</em></u>

   \frac{(y-k)^2}{a^2}+\frac{(x-h)^2}{b^2}+

So these two expressions are essentially the same with the only difference being the location of "a" and "b". The length of the major axis will be "2a" and the length of the minor axis will be "2b". The way I remember this is because when you have the horizontal major axis the "a" value is in the denominator of the (x-h) and I think of "x" as a horizontal value, since it moves a point horizontally. When you have a vertical major axis the "a" value is in the denominator of (y-k) and I think of "x" as a vertical value, since it moves a point vertically.

So just by looking at the graph, you can easily determine that the eclipse has a horizontal major axis. This can be further proven, since the distance from the origin on the right side is 28, and the distance from the the top to the origin is only 20.

So you could set up an equation to solve for a, since 2a = length of major axis, but since we're given the two points, the "a" value is really just the length from the origin to the right/left side, and combining these together you get the value of 2a/major axis, but you don't have to do that. So by looking at the graph you'll see the distance from the origin to the right side is 28. This means "a=28"

You can do the same thing here for the "b" value, and since the top is 20 units away from the origin, "b = 20"

So now let's set up the equation:
\frac{x^2}{28^2} + \frac{y^2}{20^2}=1

Square the values in the denominator

\frac{x^2}{784}+\frac{y^2}{400}=1

5 0
3 years ago
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