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1 year ago

When two lines intersect, are all the angles formed equal?

Mathematics

1 answer:

Thepotemich [5.8K]1 year ago

8 0

Answer: No

Step-by-step explanation:

If we don't know if the lines are parallel, we cannot conclude the angles are equal.

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What is Z^6y^3/z^6y^4

Maslowich

Answer:

The correct answer is

Z⁶Y³/Z⁶Y⁴ = 1/Y

Step-by-step explanation:

Points to remember

1). xᵃ * xᵇ = xᵃ⁺ᵇ

2). xᵃ/xᵇ = xᵃ⁻ᵇ

3). x° = 1

4). x⁻ᵃ = 1/xᵃ

The given expression is Z⁶Y³/Z⁶Y⁴

To find the simplification of expression

Z⁶Y³/Z⁶Y⁴ = Z⁶⁻⁶ * Y³⁻⁴

= Z° * Y⁻¹ = 1 * 1/Y = 1/Y

Therefore the value of given expression Z⁶Y³/Z⁶Y⁴ is 1/Y

4 0

2 years ago

What is 9,167.364 in expanded form?

Basile [38]

Answer:

9,000+100+60+7+.3+.06+.004

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Please, I need help in this ??

nignag [31]

Answer:

$\int\frac{x^{4}}{x^{4} -1}dx = x + \frac{1}{4} ln(x-1) - \frac{1}{4} ln(x+1)-\frac{1}{2} arctanx + c$

Step-by-step explanation:

$\int\frac{x^{4}}{x^{4} -1}dx$

Adding and Subtracting 1 to the Numerator

$\int\frac{x^{4} - 1 + 1}{x^{4} -1}dx$

Dividing Numerator seperately by $x^{4} - 1$

$\int 1 + \frac{1}{x^{4}-1 }\, dx$

Here integral of 1 is x +c1 (where c1 is constant of integration

$x + c1 + \int\frac{1}{(x-1)(x+1)(x^{2}+1)}\, dx$ ----------------------------------(1)

We apply method of partial fractions to perform the integral

$\frac{1}{(x-1)(x+1)(x^{2}+1)}$ = $\frac{A}{x-1} + \frac{B}{x+1} + \frac{C}{x^{2} + 1}$ ------------------------------------------(2)

$\frac{1}{(x-1)(x+1)(x^{2}+1)} = \frac{A(x+1)(x^{2} +1) + B(x-1)(x^{2} +1) + C(x-1)(x+1)}{(x-1)(x+1)(x^{2} +1)}$

1 = $A(x+1)(x^{2} +1) + B(x-1)(x^{2} +1) + C(x-1)(x+1)$ -------------------------(3)

Substitute x= 1 , -1 , i in equation (3)

1 = A(1+1)(1+1)

A = $\frac{1}{4}$

1 = B(-1-1)(1+1)

B = $-\frac{1}{4}$

1 = C(i-1)(i+1)

C = $-\frac{1}{2}$

Substituting A, B, C in equation (2)

$\int\frac{x^{4}}{x^{4} -1}dx$ = $\int\frac{1}{4(x-1)} - \frac{1}{4(x+1)} -\frac{1}{2(x^{2}+1) }$

On integration

Here $\int \frac{1}{x}dx = lnx and \int\frac{1}{x^{2}+1 } dx = arctanx$

$\int\frac{x^{4}}{x^{4} -1}dx$ = $\frac{1}{4} ln(x-1)$ - $\frac{1}{4} ln(x+1)$ - $\frac{1}{2} arctanx$ + c2---------------------------------------(4)

Substitute equation (4) back in equation (1) we get

$x + c1 + \frac{1}{4} ln(x-1) - \frac{1}{4} ln(x+1) - \frac{1}{2} arctanx + c2$

Here c1 + c2 can be added to another and written as c

Therefore,

$\int\frac{x^{4}}{x^{4} -1}dx = x + \frac{1}{4} ln(x-1) - \frac{1}{4} ln(x+1)-\frac{1}{2} arctanx + c$

4 0

3 years ago

Please help and get these points

Masja [62]

Answer:

y = 15x

Step-by-step explanation:

The biggest giveaway here is the other answers have + a whole number at the end of the equation. We would see this + as a y-intercept on the graph.

Since our line had no y-intercept and starts from zero, y =15x can be used to represent the graph shown

Another way to know this is to look at the points marked on the line. There is a point at (2, 30). By plugging these co-ordinated into y = 15x we get 30 = 30, which makes sense

6 0

2 years ago

Read 2 more answers

Plot the points (2,0) and (2,-5) on the coordinate plane below.

Bess [88]

Answer:

5 units

Step-by-step explanation:

Notice that the x-coordinate is the same for both points, but that the y-coordinates differ by five units. The distance between these two points is therefore 5 units.

8 0

3 years ago