Question

The distance between the points (1,2) and (x,-1) is 5 units. Find the possible values of x​

Answer 1

Answer:

-3,5

Step-by-step explanation:

$d = \sqrt{(x _{2} - x _1) {}^{2} + (y _{2} - y _{1} {} ) {}^{2} }$

$5 = \sqrt{(x - 1) {}^{2} + ( - 1 - 2) {}^{2} }$

$5 = \sqrt{(x - 1) {}^{2} + ( - 3) {}^{2} }$

$25 = (x - 1) {}^{2} + 9$

$16 = (x - 1) {}^{2}$

$4 = x - 1$

$x = 5$

Or

$- 4 = x - 1$

$x = - 3$