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EastWind [94]
2 years ago
14

The distance between the points (1,2) and (x,-1) is 5 units. Find the possible values of x​

Mathematics
1 answer:
Mariulka [41]2 years ago
7 0

Answer:

-3,5

Step-by-step explanation:

d =  \sqrt{(x _{2}  - x _1)  {}^{2} + (y _{2} - y _{1} {} ) {}^{2}  }

5 =  \sqrt{(x - 1) {}^{2} + ( - 1 - 2) {}^{2}  }

5 =  \sqrt{(x - 1) {}^{2} + ( - 3) {}^{2}  }

25 = (x - 1) {}^{2}  + 9

16 = (x - 1) {}^{2}

4 = x - 1

x = 5

Or

- 4 = x - 1

x =  - 3

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\frac{2x}{3x}  \times 120 \\= 80

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Hope it helps!!!

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ollegr [7]

The question is incomplete :

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6 0
3 years ago
(1/27)^x-6=27<br><br>Could I please have a step by step as well? Much appreciated! ​
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Answer:

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Step-by-step explanation:

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2) Multiply both sides by 27^x - 8.

1 =  {27} \times 27^{1 + x  - 8}

3) Use the product rule: x^a x^b = x^a+b.

1 =  {27}^{1 + x - 8}

4) Simplify 1 + x - 8 to x - 7.

1  =  {27}^{x - 7}

5) Use Definition of Common Logarithm: b^a = x if and only if log<u>b</u><u> </u>(x) = a.

log_{27}1 = x - 7

6) Use Change of Base Rule.

\frac{ log_1  }{  log{27} }  = x - 7

7) Use rule of 1: log 1 = 0.

\frac{0}{ log_{27}}  = x - 7

8) Simplify 0/log_27 to 0.

0 = x - 7

9) Add 7 to both sides.

7 = x

10) Switch sides.

x = 7

<u>Therefor</u><u>,</u><u> </u><u>the</u><u> </u><u>answer</u><u> </u><u>is</u><u> </u><u>x</u><u> </u><u>=</u><u> </u><u>7</u><u>.</u>

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