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3 years ago

6/12 + 1/3 with steps?

Mathematics

2 answers:

inessss [21]3 years ago

8 0

10/12=5/6 find common denominator 12 would be factor here 6/12+4/12= 10/12 reduced to 5/6

victus00 [196]3 years ago

8 0

Well I will help!

Step 1: Convert the fractions the make the the denominator(bottom number)the same.
1/3* 4/4 = 4/12

Step 2: You will want to add the numerator(top number) on both fractions
6+4=10
Step 3: Don't add the denominator! Just put the answer for the previous step n top.Simplify the answer is needed.

Answer: 10/12 Simplified Answer: 5/6

Hope this helps!

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(t-4)(3t+1)(t+2)=0 hats the answer

trasher [3.6K]

(3t² +t -12t - 4)(t+2)=0
(3t³ - 5t² -26t -8) =0
t = -2

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2 years ago

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4x + y = 7 3x + 2y = 9

Diano4ka-milaya [45]

Answer:

x = 1

y = 3

Step-by-step explanation:

<h2>Substitution Method:</h2>

Step 1:

Name The Equation

4x + y = 7 ...(1)

3x + 2y = 9 ...(2)

Step 2:

From Equation (1) we get,

4x = 7 - y

i.e.,

x = 7 - y/4

Step 3:

Substitute the value of x = 7 - y/4 in equation (2)

i.e.,

3(7 - y/4) + 2y = 9

21 - 3y/4 + 2y = 9

21 - 3y + 8y/4 = 9

21 - 3y + 8y = 9 * 4

21 + 5y = 36

5y = 36 - 21

5y = 15

y = 15/5

y = 3

Step 4:

Substitute the value of y = 3 in equation (1)

4x + y = 7

i.e.,

4x + (3) = 7

4x + 3 = 7

4x = 7 - 4

4x = 4

x = 4/4

x = 1

<h2>Verification: </h2>

4x + y = 7 i.e., 4(1) + (3) = 7

3x + 2y = 9 i.e., 3(1) + 2(3) = 9

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2 years ago

What is 72/5 in decimal form

horsena [70]

Answer:

14.4

Step-by-step explanation:

72/5 in decimal form equals 14.4

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2 years ago

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If m∠JKM = 43, m∠MKL = (8 - 20), and m∠JKL = (10x - 11), find each measure.

Brut [27]

Correct Question: If m∠JKM = 43, m∠MKL = (8x - 20), and m∠JKL = (10x - 11), find each measure.

1. x = ?

2. m∠MKL = ?

3. m∠JKL = ?

Answer/Step-by-step explanation:

Given:

m<JKM = 43,

m<MKL = (8x - 20),

m<JKL = (10x - 11).

Required:

1. Value of x

2. m<MKL

3. m<JKL

Solution:

1. Value of x:

m<JKL = m<MKL + m<JKM (angle addition postulate)

Therefore:

$(10x - 11) = (8x - 20) + 43$

Solve for x

$10x - 11 = 8x - 20 + 43$

$10x - 11 = 8x + 23$

Subtract 8x from both sides

$10x - 11 - 8x = 8x + 23 - 8x$

$2x - 11 = 23$

Add 11 to both sides

$2x - 11 + 11 = 23 + 11$

$2x = 34$

Divide both sides by 2

$\frac{2x}{2} = \frac{34}{2}$

$x = 17$

2. m<MKL = 8x - 20

Plug in the value of x

m<MKL = 8(17) - 20 = 136 - 20 = 116°

3. m<JKL = 10x - 11

m<JKL = 10(17) - 11 = 170 - 11 = 159°

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2 years ago

If ΔABC ≅ΔDEF, then what corresponding parts are congruent?

const2013 [10]

The part of the triangles which are congruent according to the description are; segment AB and segment DE.

<h3>Which parts of the triangles are congruent?</h3>

It follows from the task content that the two triangles ABC and DEF have been established as congruent. On this note, it can be established that by the congruence theorem that corresponding sides which are congruent and whose ratios equal to a constant ratio are segments AB and segment DE.