(3t² +t -12t - 4)(t+2)=0
(3t³ - 5t² -26t -8) =0
t = -2
Answer:
x = 1
y = 3
Step-by-step explanation:
<h2>
<em><u>Substitution Method</u></em><em><u>:</u></em></h2>
Step 1:
Name The Equation
4x + y = 7 ...(1)
3x + 2y = 9 ...(2)
Step 2:
From Equation (1) we get,
4x = 7 - y
i.e.,
x = 7 - y/4
Step 3:
Substitute the value of <em><u>x = 7 - y/4</u></em> in equation (2)
i.e.,
3(7 - y/4) + 2y = 9
21 - 3y/4 + 2y = 9
21 - 3y + 8y/4 = 9
21 - 3y + 8y = 9 * 4
21 + 5y = 36
5y = 36 - 21
5y = 15
y = 15/5
<em><u>y = 3</u></em>
Step 4:
Substitute the value of <em><u>y = 3</u></em> in equation (1)
4x + y = 7
i.e.,
4x + (3) = 7
4x + 3 = 7
4x = 7 - 4
4x = 4
x = 4/4
<em><u>x = 1</u></em>
<h2><em><u>Verification</u></em><em><u>:</u></em><em><u> </u></em></h2>
4x + y = 7 i.e., <em>4(1) + (3) = 7</em>
3x + 2y = 9 i.e., <em><u>3(1) + 2(3) = 9</u></em>
Answer:
14.4
Step-by-step explanation:
72/5 in decimal form equals 14.4
Correct Question: If m∠JKM = 43, m∠MKL = (8x - 20), and m∠JKL = (10x - 11), find each measure.
1. x = ?
2. m∠MKL = ?
3. m∠JKL = ?
Answer/Step-by-step explanation:
Given:
m<JKM = 43,
m<MKL = (8x - 20),
m<JKL = (10x - 11).
Required:
1. Value of x
2. m<MKL
3. m<JKL
Solution:
1. Value of x:
m<JKL = m<MKL + m<JKM (angle addition postulate)
Therefore:

Solve for x


Subtract 8x from both sides


Add 11 to both sides


Divide both sides by 2


2. m<MKL = 8x - 20
Plug in the value of x
m<MKL = 8(17) - 20 = 136 - 20 = 116°
3. m<JKL = 10x - 11
m<JKL = 10(17) - 11 = 170 - 11 = 159°
The part of the triangles which are congruent according to the description are; segment AB and segment DE.
<h3>Which parts of the triangles are congruent?</h3>
It follows from the task content that the two triangles ABC and DEF have been established as congruent. On this note, it can be established that by the congruence theorem that corresponding sides which are congruent and whose ratios equal to a constant ratio are segments AB and segment DE.
Read more on congruence theorem;
brainly.com/question/2102943
#SPJ1