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never [62]
2 years ago
9

PLSSS HELP IF YOU TURLY KNOW THISS

Mathematics
2 answers:
Amanda [17]2 years ago
7 0

Answer:

1 5/6 > 1 2/3

Step-by-step explanation:

=>        1 5/6 = (1*6)+5/6

=>        1 5/6 = 6+5/6

=>        1 5/6 = 11/6

so like that, 1 2/3 = 5/3

now the denominators should be the same

for that,

5*2/3*2 = 10/6

11/6 and 10/6

=>          11/6 > 10/6

=>          1 5/6 > 1 2/3

Ainat [17]2 years ago
5 0

Answer:

answer "Less than"

Step-by-step explanation:

a) 1 2/3 = 5/3 = 1.666 ...

b) 1 5/6 = 11/6 = 1.833 ...

a < b

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Write the equation that represents the line graphed below​
rodikova [14]

Answer:

(2,-6)

Step-by-step explanation:

If it's not that then(-6,2)

But if it's not either i'm sorry

7 0
2 years ago
Help please!! Stuck on this question!! ∠ABC is adjacent to ∠CBD. If the m∠ABC=4x+23, m∠CBD=6x+7, and m∠ABD=130°, what is the mea
Ulleksa [173]

Answer:

63 degrees

Step-by-step explanation:

add 4x + 23 and 6x + 7, then equal that to 130. When you find x, plug it into 4x+23 and get 63.

3 0
3 years ago
6[ 5x (41-36) - (8+14)]
IgorLugansk [536]

Answer:

=18

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
What is the slope of (9,5) and (21-,5)
kondor19780726 [428]

Answer:

\frac{y2-y1}{x2-x1} \\\frac{-5-5}{21-9}\\ \frac{-10}{12} \\-\frac{5}{6}

Step-by-step explanation:

4 0
1 year ago
Read 2 more answers
What is the center of the circle that you can circumscribe about a triangle with vertices A(2, 6), B(2, 0), and C(10, 0)?
denis23 [38]
The three points A,B,C are all points on this circle.
Each point is then equal distance from the center, that distance being the radius of the circle.
Using the distance formula, we can find the center of the circle  (x,y):
d^2 = (x-x_0)^2 + (y-y_0)^2
Plugging in points A and B into distance formula, then setting them equal to each other gives:
(x-2)^2+(y-6)^2 = (x-2)^2 + y^2
Right away we can cancel out the x terms leaving:
(y-6)^2 = y^2
Expand Left side and Solve for y:
y^2 -12y +36 = y^2
y = 3
Plug in points B and C as before:
(x-2)^2 + y^2 = (x-10)^2 + y^2
Here we can cancel the y-terms.
Expand and solve for x:
x^2 -4x+4 = x^2 -20x+100
16x = 96
x = 6
Therefore the center of the circle is the point (6,3)
6 0
3 years ago
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