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Alinara [238K]
3 years ago
5

A number cube has faces numbered 1 to 6.

Mathematics
2 answers:
Arturiano [62]3 years ago
7 0

Answer:

Hmmmm, what I think is you are 100% right if I'm wrong put it in the comment please, Thanks!

nikdorinn [45]3 years ago
5 0

Answer:

yes

Step-by-step explanation:

your right

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Jodie bought some shirts for $6 each. Marge bought some shirts for $8 each. The girls spent the same amount of money on shirts.
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$24.00   i hope this helped you
                                                                                                  
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3 years ago
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Solve pls brainliest
Oksana_A [137]

Answer:

y = 13x

Step-by-step explanation:

Substitute 2 in x and you'll get 26:

y = 13•2

y = 26

4 0
3 years ago
Jane draws a line in the coordinate plane that passes through the points (2,3) and (6,9)
timofeeve [1]

Answer:

y=x+1

Step-by-step explanation:

To find the line of the equation, use the slope formula to find the slope.

Slope formula is: y2-y1/x2-x1

9-3/6-2= 3/4

Once you have the slope, use that and one of the coordinates to put the equation in point-slope form.

Point-slope form is: y-y1=m(x-x1), with m representing slope and y1 and x1 representing the x and y coordinates.

y-3=1(x-2)

With the equation in point-slope form, you can now distribute 1 to x-2 and simplify to put it in slope-intercept form.

y-3=1x-2

y=x+1

3 0
3 years ago
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<img src="https://tex.z-dn.net/?f=The%20%5C%3A%20%20value%20%20%5C%3A%20of%20%20%5C%3A%20%20%5Csqrt%7B6%20%2B%20%20%5Csqrt%7B6%2
saul85 [17]

\large\underline{\sf{Solution-}}

<u>Let us assume that:</u>

\sf \longmapsto x =  \sqrt{6 +  \sqrt{6 +  \sqrt{6 + ... \infty } } }

We can also write it as:

\sf \longmapsto x =  \sqrt{6 +  x }

Squaring both sides, we get:

\sf \longmapsto  {x}^{2}  =6 +  x

\sf \longmapsto  {x}^{2} - x - 6  =0

By splitting the middle term:

\sf \longmapsto  {x}^{2} - 3x + 2x - 6  =0

\sf \longmapsto x(x - 3) + 2(x - 3 ) =0

\sf \longmapsto (x+ 2)(x - 3 ) =0

<u>Therefore:</u>

\longmapsto\begin{cases} \sf (x+ 2) =0 \\ \sf (x - 3) = 0 \end{cases}

\sf \longmapsto x =  - 2,3

<u>But x cannot be negative. </u>

\sf \longmapsto x = 3

Therefore, the value of the expression is 3.

\large\underline{\sf{Verification-}}

Given:

\sf\longmapsto x=3

We can also write it as:

\sf\longmapsto x = \sqrt{9}

\sf\longmapsto x = \sqrt{6+3}

\sf\longmapsto x = \sqrt{6 + \sqrt{9}}

\sf\longmapsto x = \sqrt{6 + \sqrt{6+3}}

\sf\longmapsto x = \sqrt{6 + \sqrt{6+\sqrt{9}}}

\sf\longmapsto x = \sqrt{6 + \sqrt{6+\sqrt{6+3}}}

This pattern will continue.

\sf\longmapsto x = \sqrt{6 + \sqrt{6+\sqrt{6+...\infty}}}

7 0
3 years ago
Given: quadrilateral MNOL with MN ≅ LO and ML ≅ NO
mr_godi [17]
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Based on CPCTC, all of the corresponding angles of △MLO and △ONM are congruent as well since the two triangles are congruent, that is,   
     ∠LMO≅∠NOM and ∠NMO≅∠LOM.
Since the pair ∠LMO and ∠NOM as well as ∠NMO and ∠LOM are angles on the inner side of two lines but on opposite sides of the transversal MO, these pairs of angles are also alternate interior angles.
5 0
3 years ago
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