A. Which reduction should she use so the picture fills as much of the frame as possible, without being too large?
Find the scale factor to get rom 7 1/3 inches to 5 1/3 inches:
5 1/3 / 7 1/3 = 0.7272
Now rewrite the fraction as decimals:
2/3 = 0.667
¾ = 0.75
5/9 = 0.555
The closest scale that would still fit the frame would be 2/3 because it is under 0.727.
B. How much extra space is there in the frame when she uses the reduction from Part A?
Multiply the original size by the scale factor to use:
7 1/3 x 2/3 = 4 8/9
Now subtract the scaled size from the original size:
7 1/3 – 4 8/9 = 2 4/9 inches extra
C. If she had a machine that could reduce by any amount, so that she could make the reduced picture fit in the frame exactly, what fraction would the reduction be?
Convert the scale from part A to a fraction:
0.72 = 72/99 which reduces to 8/11
I’m pretty sure this is the answer
128, -256
|x - 1| > 4 ⇔ x - 1 > 4 or x - 1 < -4 |add 1 to both sides
x > 5 or x < -3
Answer: c. {x| x < -3 or x > 5}.
The first is C. r = 4(4/9)
the second one is B. h = 130
the second one is A. k = 7
i’m so sorry, they’re all wrong
Answer:
9 months
Step-by-step explanation:
Given
Fabulous fitness charges a one-time fee of $90 and an additional $25 per month
let the number of months be x
and the total charges be y
y= 25x+90---------1
Wonder weights charges a one-time fee of only $ 27 dollars but charge an additional $32 each month
let the number of months be x
and the total charges be y
y= 32x+27------------2
Required
The value of x, that is the number of months
Step two:
Equating both equations we have
25x+90=32x+27
collect like terms
25x-32x=27-90
-7x=-63
7x=63
divide both sides by 7
x= 63/7
x= 9 months
