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-Dominant- [34]
2 years ago
9

P1 = (1,5). P2 = (x,2) .p1p2=5 ​

Mathematics
1 answer:
Alex787 [66]2 years ago
6 0

\qquad\qquad\huge\underline{{\sf Answer}}♨

Let's use distance formula :

\qquad \sf  \dashrightarrow \: \sqrt{(x - 1) {}^{2}  +  (2 - 5) {}^{2} } = 5

\qquad \sf  \dashrightarrow \: {(x - 1) {}^{2}  +  ( - 3) {}^{2} } = 5 {}^{2}

\qquad \sf  \dashrightarrow \:(x - 1) {}^{2}  + 9 = 25

\qquad \sf  \dashrightarrow \:(x - 1) {}^{2}  = 16

\qquad \sf  \dashrightarrow \:(x - 1) = 16

\qquad \sf  \dashrightarrow \:(x - 1) =  \pm4

\qquad \sf  \dashrightarrow \:x = 5 \:  \: or \:  \:  - 3

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Taking the natural log of both sides,

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We must solve this for r.  Raising e to the power ln (1 + r), on the left side of an equation, and raising e to the power 0. 01986 on the right side, we get:

1 + r = 3, so r must = 2.

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A = 20(1 +2)^4 (hundreds),

or

A = 20(3)^4, or

A = 81

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