All categories

2 years ago

P1 = (1,5). P2 = (x,2) .p1p2=5

Mathematics

1 answer:

Alex787 [66]2 years ago

6 0

$\qquad\qquad\huge\underline{{\sf Answer}}♨$

Let's use distance formula :

$\qquad \sf \dashrightarrow \: \sqrt{(x - 1) {}^{2} + (2 - 5) {}^{2} } = 5$

$\qquad \sf \dashrightarrow \: {(x - 1) {}^{2} + ( - 3) {}^{2} } = 5 {}^{2}$

$\qquad \sf \dashrightarrow \:(x - 1) {}^{2} + 9 = 25$

$\qquad \sf \dashrightarrow \:(x - 1) {}^{2} = 16$

$\qquad \sf \dashrightarrow \:(x - 1) = 16$

$\qquad \sf \dashrightarrow \:(x - 1) = \pm4$

$\qquad \sf \dashrightarrow \:x = 5 \: \: or \: \: - 3$

You might be interested in

lina2011 [118]

Answer:

5/14

Step-by-step explanation:

5 + 9 = 14- so our denominator is 14

Theres 5 milk chocolates, so the probability is 5/14

I hope this helped, please mark Brainliest, thank you !!

4 0

2 years ago

A triangular pyramid has a surface area of 174 square feet. It is made up of equilateral triangles with side lengths of 10 feet.

emmainna [20.7K]

Answer:

Slant height = 7.07 ft to nearest hundredth.

Step-by-step explanation:

The slant height = height of one of the triangular sides

Using Pythagoras:

S^2 = 1/2 * 10^2 + 10^2 = 50 ft.

S = √50 = 7.071

6 0

2 years ago

a city worker is painting a stripedown the center of main street. main street is 8/10 mile long the worker painted 4/10 mile of

harina [27]

Subtract 8/10 from 4/10 but just the numerator (the top number) and you will get 4/10

8 0

3 years ago

What's <br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B50%20-%201%7D%20" id="TexFormula1" title=" \sqrt{50 - 1} " alt=" \sqrt

nikklg [1K]

Inside the root is 50-1

50-1 = 49

You would remain with root 49 but, if you calculate the square root the answer would be 7 because...

7•7 = 49

^ So, the answer is 7

4 0

2 years ago

Read 2 more answers

Domain and Range for the function f(x)=5IXI is

shutvik [7]

Answer:

The domain of the function f(x) is:

$\mathrm{Domain\:of\:}\:5\left|x\right|\::\quad \begin{bmatrix}\mathrm{Solution:}\:&\:-\infty \:$

The range of the function f(x) is:

$\mathrm{Range\:of\:}5\left|x\right|:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:f\left(x\right)\ge \:0\:\\ \:\mathrm{Interval\:Notation:}&\:[0,\:\infty \:)\end{bmatrix}$

Step-by-step explanation:

Given the function

$f\left(x\right)=5\left|x\right|$

Determining the domain:

We know that the domain of the function is the set of input or arguments for which the function is real and defined.

In other words,

Domain refers to all the possible sets of input values on the x-axis.

It is clear that the function has undefined points nor domain constraints.

Thus, the domain of the function f(x) is:

$\mathrm{Domain\:of\:}\:5\left|x\right|\::\quad \begin{bmatrix}\mathrm{Solution:}\:&\:-\infty \:$

Determining the range:

We also know that range is the set of values of the dependent variable for which a function is defined.

In other words,

Range refers to all the possible sets of output values on the y-axis.

We know that the range of an Absolute function is of the form

$c|ax+b|+k\:\mathrm{is}\:\:f\left(x\right)\ge \:k$

$k=0$

Thus, the range of the function f(x) is:

$\mathrm{Range\:of\:}5\left|x\right|:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:f\left(x\right)\ge \:0\:\\ \:\mathrm{Interval\:Notation:}&\:[0,\:\infty \:)\end{bmatrix}$

7 0

3 years ago

P1 = (1,5). P2 = (x,2) .p1p2=5 ​

P1 = (1,5). P2 = (x,2) .p1p2=5