Answer:
A) Technician A says a fuel injector pulsed flow test measures steady or maximum fuel flow with the injector pintle and nozzle held fully open.
Explanation:
Through the fuel injector the fuel is injected, and the fuel injector pulsed flow test helps us understand the functioning of the machine at various pulse width, and varying fuel flow ranging from the least to the maximum. The first one is definitely a situation. And hence Technician A is definitely correct. However, Technician B is not correct, as for checking the pintle response you need to change the pulse width. However, technician B is mentioning that he always test with normal pulse width, and this is definitely not true. Hence Technician A is the right person.
Answer:
D)to show that the situation was tense for everyone
Explanation:
got it right on edge
The ways operands fetched from or stored into memory using different ways are :
- Immediate mode
- Register
- Register indirect (the value is stored in the memory)
- Indirect
- A couple of Hybrid modes
- Stack addressed
Hope this helps
Answer:
- #include <iostream>
- using namespace std;
- int hailstoneLength(int n){
- int term = 1;
- while(n != 1){
- if(n % 2 == 0){
- n = n / 2;
- term++;
- }
- else{
- n = n * 3 + 1;
- term++;
- }
- }
- return term;
- }
- int main()
- {
- cout<<hailstoneLength(8);
- return 0;
- }
Explanation:
Hailstone sequence is a list of number that is generated by following the rules as below:
- Given a starting number (e.g. 5)
- If the number is even, divide it by 2
- If the number is odd, multiply it by 3 and then add 1
- the starting number will either be repeatedly divided or multiplied until the final n reaches 1
So, we can create a function called hailstoneLength that takes one input number, n, as starting number (Line 4).
In the function initialize the variable term with value of 1 (Line 5). Create a while loop and set the condition to enable the loop running until the n become 1 (Line 6). In the loop, keep checking the n value if it is currently even or odd using modulus operator (Line 7 - 14). If it is even, divide n by 2 and increment the term by one (Line 7 - 10). If it is odd, multiple it by 3 and add 1 (Line 11 - 14). At last, return term value as output (Line 16).
In the main program, test the function by passing 8 as argument. We shall get the output of 4 (Line 21).
Answer:
server
Explanation:
it has ability to connect all computers to the network
