Answer:
a microscopic organism, especially a bacterium, virus, or fungus.
Explanation:
The best and most correct answer among the choices provided by the question is <span>C. Using more than one assessment provides a more complete picture of an individual's fitness level.</span>
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Hope my answer would be a great help for you. </span>
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Answer:
This question lacks options, options are:
A) ATP
B) NADP
C) Pryuvate
D) glucose
E) acetyl-CoA.
The correct answer is C) Pyruvate.
Explanation:
Pyruvate is a very important compound for the cell since it is a key substrate for energy production and glucose synthesis (neo-glycogenesis), that is, pyruvate is the end product of glucose breakdown in glycolysis. Before entering the mitochondria, it can be converted to lactate, through an anaerobic reaction (in the absence or under oxygen supply) of low performance in energy production, when the main pathway is interfered with. It can also be converted to the amino acid alanine. Within the mitochondria, it can be transformed, by pyruvate dehydrogenase (PDH), into acetyl-coenzyme A (acetyl-CoA), the entry point (substrate) of the Krebs cycle. In addition, by means of pyruvate carboxylase, it can be transformed into oxalacetate, which constitutes the first step in neoglycogenesis.
The right answer is metaphase II.
The process is performed in two nuclear and cytoplasmic divisions, called first and second meiotic division or simply meiosis I and meiosis II. Both include prophase, metaphase, anaphase, and telophase. First division prophase is long and consists of 5 stages: leptotene, zygotene, pachytene, diplotene, and diakinesis. It is at this point that genetic recombination takes place at the level of chiasmus.
During meiosis I, the members of each homologous pair of chromosomes are paired during prophase, forming bivalents. During this phase, a protein structure, called synaptonemal complex form, allows recombination between homologous chromosomes. Subsequently, a large condensation of the bivalent chromosomes occurs and go to the metaphase plate during the first metaphase, resulting in the migration of n chromosomes to each of the poles during the first anaphase. This reduction division is responsible for maintaining the number of chromosomes characteristic of each species.
In meiosis II, as in mitosis, the sister chromatids comprising each chromosome are separated and distributed between the nuclei of the daughter cells. Between these two successive steps, there is no DNA replication. The maturation of the daughter cells will result in the gametes.
The answer would be c) to form images from sensory signals
