Answer:
x-6
Step-by-step explanation:
The mistake when expanding the bracket 3(x-6),3 was supposed to multiply 6 but instead it was added to 6 instead
the correct working
3(x-6)+(4x+12)-6x
3x-18+4x+12-6x
(3x+4x-6x)+(-18+12)
=x-6
Answer:
3x³ + x² + x + 1
= 3x³ - 3x² + 4x² - 4x + 5x - 5 + 6
= 3x²(x - 1) + 4x(x - 1) + 5(x - 1) + 6
= (x - 1)(3x² + 4x + 5) + 6
but 3x³ + x² + x + 1 = (x - 1).Q(x) + R
=> Q(x) = 3x² + 4x + 5
R = 6
Y=ab^x
logab=x
log7(1/343)=-3
y=7(1/343)^-3
Let the number be x
2/3*x - 2 = 10
or, 2/3 * x =12
or x= 12*3/2
or, x = 18
