Answer:
Accoridng to your question we have to find the square root of 0.0025
However students face some problem in finding square roots of number in decimal but it is too easy to find .
√0.0025
0.05 is the square root of 0.0025
after decimal there are two zero and by square root there will be one zero and 25 is the square root of 5 .
so thus we find the square root amd the correct answer is 0.05
Answer:
The answer to your question is the third option The x- and y coordinates are switched.
Step-by-step explanation:
Remember that to plot a point there will be a pair of numbers separated by a comma.
The first number is the x coordinate and the second number is the y-coordinate.
In this problem, number 4 is the x-coordinate and -1.5 is the y-coordinate.
Look for the x-coordinate in the horizontal axis and y-coordinate in the vertical axis.
Answer:
C
Step-by-step explanation:
p³ - 216q³ ← is a difference of cubes and factors in general as
a³ - b³ = (a - b)(a² + ab + b²) , then
p³ - 216q³
= p³ - (6q)³
= (p - 6q)(p² + 6pq + 36q²) → C
Answer:
c) 6x - 5y = 15
Step-by-step explanation:
Slope-intercept form of a linear equation: ![y=mx+b](https://tex.z-dn.net/?f=y%3Dmx%2Bb)
(where m is the slope and b is the y-intercept)
Maria's line: ![y=-\dfrac{5}{6}x+8](https://tex.z-dn.net/?f=y%3D-%5Cdfrac%7B5%7D%7B6%7Dx%2B8)
Therefore, the slope of Maria's line is ![-\frac{5}{6}](https://tex.z-dn.net/?f=-%5Cfrac%7B5%7D%7B6%7D)
If two lines are perpendicular to each other, the product of their slopes will be -1.
Therefore, the slope of Nate's line (m) is:
![\begin{aligned}\implies m \times -\dfrac{5}{6} &=-1\\m & =\dfrac{6}{5}\end{aligned}](https://tex.z-dn.net/?f=%5Cbegin%7Baligned%7D%5Cimplies%20m%20%5Ctimes%20-%5Cdfrac%7B5%7D%7B6%7D%20%26%3D-1%5C%5Cm%20%26%20%3D%5Cdfrac%7B6%7D%7B5%7D%5Cend%7Baligned%7D)
Therefore, the linear equation of Nate's line is:
![y=\dfrac{6}{5}x+b\quad\textsf{(where b is some constant)}](https://tex.z-dn.net/?f=y%3D%5Cdfrac%7B6%7D%7B5%7Dx%2Bb%5Cquad%5Ctextsf%7B%28where%20b%20is%20some%20constant%29%7D)
Rearranging this to standard form:
![\implies y=\dfrac{6}{5}x+b](https://tex.z-dn.net/?f=%5Cimplies%20y%3D%5Cdfrac%7B6%7D%7B5%7Dx%2Bb)
![\implies 5y=6x+5b](https://tex.z-dn.net/?f=%5Cimplies%205y%3D6x%2B5b)
![\implies 6x-5y=-5b](https://tex.z-dn.net/?f=%5Cimplies%206x-5y%3D-5b)
Therefore, <u>option c</u> could be an equation for Nate's line.